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vlada-n [284]
3 years ago
6

Identify what algorithm or concept the following code relates to. void Sort(int array[], int tempArray[], int left, int right) {

int i, j, k, middle; if(right > left) { middle
Computers and Technology
1 answer:
galina1969 [7]3 years ago
4 0

Answer:

Binary sort

Explanation:

Binary sort is one of the fastest search techniques used on arrays and other iterable data types. It algorithm sorts the array in ascending order then gets the item in the middle from which it divides the array to be searched in two parts. If the searched term is less than the mid item, then it is searched for in the first part, else it would be in the second.

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stira [4]

Answer:

why do you need help

Explanation:

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8 0
3 years ago
Write a program that displays a menu allowing the user to select air water, or steel. After the user has made a selection, the n
luda_lava [24]

Answer:

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main ()

{

// Declare Variable

int selection;

// Prompt user to make a selection of medium between air, water or steel.

cout<<"Make Selection"<<'\n'<<"Press 1 for Air"<<'\n'<<"Press 2 for Water"<<'\n'<<"Press 3 for Steel";

cin>>selection;

// Check for entry

if(selection == 1) {

cout<<"You selected Air"<<'\n';

cout<<"The distance travelled by sound wave in air is 1,125 feet in 1 second";

}

else if(selection == 2) {

cout<<"You selected Water"<<'\n';

cout<<"The distance travelled by sound wave in water is 4859 feet in 1 second";

}

else if(selection == 3) {

cout<<"You selected Steel"<<'\n';

cout<<"The distance travelled by sound wave in steel is 19554 feet in 1 second";

}

else

cout<<"Invalid Selection";

return 0;

}

7 0
3 years ago
How does a cloud-first strategy differ from other approaches to cloud?
Irina18 [472]

Cloud-first strategy differ from other approaches as It keeps all the services performed by legacy systems while moving to the Cloud in a staggered approach.

<h3>What is a cloud first strategy?</h3>

The change of cloud computing has brought about  “cloud-first” strategy.

This  is known to be a way to computing that tells that a firm should look first to cloud solutions when creating new processes or taking in old processes before taking in non-cloud-based solutions.

Note that Cloud-first strategy differ from other approaches as It keeps all the services performed by legacy systems while moving to the Cloud in a staggered approach.

See options below

it enables an organization to completely move to the cloud without infrastructure or support requirement

it keeps all the services performed by legacy systems while moving to the cloud in a staggered approach.

it partners technology with multiple other disciplines for comprehensive business transformation.

it uses artificial intelligence to automate all business processes and completely eliminate human error.

Learn more about cloud from

brainly.com/question/19057393

#SPJ1

6 0
2 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
A browser is an example of a<br>​
Inessa [10]

Answer:

User Interface, Website

3 0
3 years ago
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