A. because the form is about stories from events in a writer's life
Answer:
"Cross-training
" seems to be the right response.
Explanation:
- Cross-training seems to be the method of constructing a multi-professional workers staff with incentive plans to make sure that they must have the same tools to complete different occupational tasks throughout the organization.
- This will be a very broad approach besides randomized controlled training methods, both maximum and minimum frequency, for generations.
Answer:
Hi there! The answer is C:
Explanation:
The scope of the LOWER function is limited to the select clause it is being used in. Outside of the select statement, the column will be returned as it is currently present in the database. Using the LOWER function will not automatically store data in lower case letters in the database tables. As an exercise, try creating a simple database table called "Employees" with columns "id" and "name". Then input a row using an insert statement with id as 1 and name as "BLAH". Try using the select statement with LOWER function and then without the LOWER statement.
Answer:
Stack.
Explanation:
Topological sort requires a bit of addition to DFS algorithm.So DFS can be done by two ways that are either you can use recursion or you can use Stack data structure to implement DFS.
Since recursion uses stack memory when it makes recursive calls and if you want to do it iteratively you can stack data structure.
Answer:
see explaination
Explanation:
#include <iostream>
#include <string>
using namespace std;
class LinkedList{
class Node{
public :
int data;
Node* next;
Node(int data){
this->data = data;
next = NULL;
}
};
public :
Node *head;
LinkedList(){
this->head = NULL;
}
void insert(int d){
Node* new_node = new Node(d);
new_node->next = head;
head = new_node;
}
// sort the list with selection sort algorithm.
// Pick the smallest element in the unsorted array and place in the first element in the unsorted.
void sort_list(){
if (head == NULL){
return;
}
Node* current = head;
while (current->next != NULL){
Node* min_node = current;
Node* traverse = current->next;
while(traverse != NULL){
if(traverse->data < min_node->data){
min_node = traverse;
}
traverse = traverse->next;
}
int temp = current->data;
current->data = min_node->data;
min_node->data = temp;
current = current->next;
}
}
void print_list(){
Node* current = head;
while(current !=NULL){
cout<<current->data<<" ";
current = current->next;
}
cout<<"\n";
}
};
int main(){
LinkedList ll;
for(int i=0;i<10;i++){
ll.insert(i);
}
ll.print_list();
cout<<"*******************************************\n";
ll.sort_list();
ll.print_list();
cout<<"*******************************************\n";
}