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Alexxx [7]
3 years ago
13

Two stores sell the same computer for the same original price. Store A advertises that the computer is on sale for 25% off the o

riginal price. Store B advertises that it is reducing the computer’s price by $180. When Brittany compares the sale prices of the computer in both stores, she concludes that the sale prices are equal. Let p represent the computer’s original price. Which equation models this situation?
Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Answer:

p= 25/100 = 180/x

Step-by-step explanation:

In order to find the computer's original price, you must use the equation p= 25/100 = 180/x and solve for x.

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Destini wants to buy a scarf for her mother. The original price of the scarf is $26.00, not including tax. The scarf is on sale
sergij07 [2.7K]
$21.80 because you will do 20% over 100% = x over $26. Than you will do 26 times 20 divided by 100, and you get 5.2, than you will do 26-5.2 and you get $21.80
5 0
2 years ago
Write this sentence as an equation? <br><br> Six less than 4 times a number gives 18
agasfer [191]

Answer:

6-4 times x=18

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4 0
3 years ago
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A square has an area of 4 ft^2 what is the lenght of each side
sergiy2304 [10]

area of square = 4ft²

a s area of square = length×lenght

let lenght =x

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x=2 ftSo lebght of each side is 2 ft.

5 0
3 years ago
there are 4 banana smoothies, 1 strawberry smoothie and 1 watermelon smoothie in the refrigerator. without looking, what is the
Mamont248 [21]

There are four banana, one strawberry and one water-melon smoothies, six in all.

Assuming all smoothies are identical when we pick, then the probability of picking a particular one is one divided by the total number (of smoothies).

Since there are four banana smoothies, the probability of picking a banana smoothie is four divided by six, or four-over-six, or two-thirds.

There are now five smoothies remaining, of which three are banana. Therefore the probability of picking another banana is three-over-five, or three fifths.

The final probability is the product of the individual (we call it a two-step experiment), or two-third multiplied by three-fifths, equal to two-fifths, or forty percent.

Recall that if the first banana smoothie had been put back in the batch, the probability would come out different.

7 0
3 years ago
In 1998, as an advertising campaign, the Nabisco Company announced a "1000 Chips Challenge," claiming that every 18-ounce bag of
Phoenix [80]

Answer:

A 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

Step-by-step explanation:

We are given that statistics students at the Air Force Academy (no kidding) purchased some randomly selected bags of cookies and counted the chocolate chips.

Some of their data are given below; 1219, 1214, 1087, 1200, 1419, 1121, 1325, 1345, 1244, 1258, 1356, 1132, 1191, 1270, 1295, 1135.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                          P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of chocolate chips = \frac{\sum X}{n} = 1238.2

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 94.3

            n = sample of car drivers = 16

            \mu = population mean number of chips in a bag

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.131 \times {\frac{s}{\sqrt{n} } } , \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ]

                                   = [ 1238.2-2.131 \times {\frac{94.3}{\sqrt{16} } } , 1238.2+2.131 \times {\frac{94.3}{\sqrt{16} } } ]

                                   = [1187.96, 1288.44]

Therefore, a 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

7 0
3 years ago
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