Answer:
9
Step-by-step explanation:
Hi there, AirConditioning,
The equation we will be using is linear, and takes the form y = slope*x+b, where slope is equivalent to the fireflies caught each minute.
y=total fireflies caught
You : y = 3m+13
Your Friend: ym+6
Fireflies caught each minute
You: 3
Your Friend: 4
3+4=7
A total of 7 fireflies each minute combined.
Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like
(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}
√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then
(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}
A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that
(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}
I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then
(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.
N is a subset of B, so
(iv.b) N - B = N = {1, 2, 3, ...}
Answer:
The surface area of the right regular hexagonal pyramid is 50.78 cm².
Step-by-step explanation:
Given:
A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.
Now, to find the surface area(SA) of the right regular hexagonal pyramid.
So, we find the area of the base(b) first:
Area of the base = ![\sqrt[3]{3}\times s^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%20s%5E%7B2%7D)
= ![\sqrt[3]{3}\times 2^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%202%5E%7B2%7D)
On solving we get:
Area of the base(b) = 
Then, we find the perimeter(p) :
Perimeter = s × 6
Now, putting the formula for getting the surface area:
Surface area = perimeter × height/2 + Area of the base.
As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>
Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².
X=5.5 is what I got when I did the math
