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lyudmila [28]
2 years ago
6

Find the point-slope equation for

Mathematics
1 answer:
Igoryamba2 years ago
4 0

Answer:

y+(21)=-4(x-7)

Step-by-step explanation:

the point slope equation , two point

m=y2-y1/x2-x1

m=23+21/-4-7=44/-11= -4

y+(21)=-4(x-7)

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What is the answer to this math question!?
Nostrana [21]

Answer:

C) 37

Step-by-step explanation:

1/2(PQ)=RQ

2.5x+17=6x-11

17=3.5x-11

28=3.5x

x=8

RQ=6(8)-11

RQ=48-11

RQ=37

5 0
2 years ago
Read 2 more answers
Tras una rebaja del 8%, un pantalón cuesta 17,28 euros. ¿Cuál era su precio inicial?
Sholpan [36]

Answer:

18.78

Step-by-step explanation:

x*(100%-8%)=17.28

x=18.78

3 0
2 years ago
In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0
3 years ago
Read 2 more answers
The graph of a line has a slope of 3 and passes through the point (–4, –5).
Alenkinab [10]

Answer

(C) y +5 =3(x+4)

We will use the point-slope formula to solve this problem.

We will use the point-slope formula to solve this problem.(y+5)=3(x+4)

)Explanation:

)Explanation:We can use the point slope formula to solve this problem.

)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)

)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.

)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.We can substitute the slope and point we were given into this formula to produce the equation we are looking for:

)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.We can substitute the slope and point we were given into this formula to produce the equation we are looking for:(y−(−5))=3(x--(4))

=> (<u>y+</u><u>5</u><u>)=3(x</u><u>+</u><u>4</u><u>)</u>

3 0
1 year ago
Suppose △LMN≅△PQR .
Tanya [424]
First four answers are correct as congruent parts of congruent triangles are congruent but L Is not the opposite to M so they wouldn’t be congruent nor does NL or PQ have the same connection
6 0
2 years ago
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