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Phoenix [80]
3 years ago
13

Which relation is a function?

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0
D) (-5,1) (4,9) (6,10)
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(1 point) In 7 years Harry and Sally would like to have $14000 for a down payment on a house. How much should they deposit each
den301095 [7]

Answer:

$110.37

Step-by-step explanation:

Assuming the monthly payment is made at the beginning of the month, the formula for the monthly payment P that gives future value A will be ...

... A = P(1+r/12)((1+r/12)^(nt) -1)/(r/12) . . . . n=compoundings/year, t=years

... 14000 = P(1+.11/12)((1+.11/12)^(12·7) -1)/(.11/12)

... 14000 = P(12.11)((1+.11/12)^84 -1)/0.11 ≈ P·126.84714 . . . . fill in the given values

... P = 14000/126.84714 = 110.37 . . . . . divide by the coefficient of P

They should deposit $110.37 at the beginning of each month.

6 0
3 years ago
Evaluate the formula V=BH/3 for B=4cm^2 and h=6 cm
Tom [10]
V=BH/3
V=(4)(6)/3
V=(24)/3
V=8
6 0
3 years ago
Read 2 more answers
15 POINTSSS AND BRAINLIEST
Ludmilka [50]
1.) 52:97.5
2.) 1:1.875

Hope this helps!
5 0
3 years ago
If the critical z-value for a hypothesis test... If the critical z-value for a hypothesis test equals 2.45, what value of the te
schepotkina [342]

Answer: z score = 0.00714

Step-by-step explanation: the value of test statistics is gotten using the standard normal distribution table.

Z= 2.45 has area to the left (z<2.45) and area to the right (z>2.45).

Level of significance α is the probability of committing a type 1 error. The area under the distribution is known as the rejection region and it is the area towards the right of the distribution.

The table I'm using is towards the left of the distribution.

But z>2.45 + z<2.45 = 1

z> 2.45 = 1 - z<2.45

But z < 2.45 = 0.99286

z > 2.45 = 1 - 0.99286

z >2.45 = 0.00714

Hence the test statistics that would produce the least type 1 error is 0.00714

8 0
3 years ago
Which expression is equivalent to 4^ 5x4^ -7÷4 ^-2?
Andre45 [30]

\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad  a^n\implies \cfrac{1}{a^{-n}}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4^5\cdot 4^{-7}\div 4^{-2}\implies \cfrac{4^5\cdot 4^{-7}}{4^{-2}}\implies \cfrac{4^{5-7}}{4^{-2}}\implies \cfrac{4^{-2}}{4^{-2}}\implies 4^{-2}\cdot 4^2 \\\\\\ 4^{-2+2}\implies \boxed{4^0}\implies 1

5 0
3 years ago
Read 2 more answers
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