1425/100=(57•25)/(4•25)
=57/4
=14 1/4
If a = 6l^2 is the total area of the surface of a cube with sides l length and A = 6 (2l)^2 is that area with 2l sides, then we take the ratio A/a = 6 (2l)^2/(6 l^2) = (2l)^2/l^2 = 4l^2/l^2 = 4. So that A = 4a. And that explicitly shows that the area A with 2l for sides is 4 X a, where a is the area when l is the side length.
<span>Using ratios to compare values of the same thing is the smart way to solve this kind of problem, because many of the values, like the 6 in both, cancel out. In fact, because we found that A/a = (2l/l)^2 we say in general that the area of a cube varies with the square of the length of its side.
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Step-by-step explanation:
If you graph the new identity, and the og identiy, they will be conciding graphs, so they are the same identity.
For this case we have the following function:
n (t) = 2400 * (5) ^ t
For n (t) = 60000 we have:
60000 = 2400 * (5) ^ t
We clear the value of t.
For this we use the logarithm:
(5) ^ t = 60000/2400
log5 ((5) ^ t) = log5 (60000/2400)
t = log5 (60000/2400)
t = 2 days
Answer:
the number of bacteria in the culture will be 60 comma 000 after:
t = 2 days
