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My name is Ann [436]

3 years ago

14

Using the numbers 2,7,13,11,5 can you get the total of 23? (No negatives, No repetitive Numbers and only)

1 answer:

choli [55]3 years ago

3 0

Answer:

7, 11, 5

Step-by-step explanation:

7 + 11 = 18

18 + 5 = 23

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What is the answer to 3/4 +1/3

Elis [28]

Well, to add fractions, you need to find a common denominator. In this case, the smallest common denominator would be 12. So you must multiply each fraction so that both denominators are 12.
3/4*3/3=9/12
1/3*4/4=4/12
Add those two fractions together, reduce if possible, and you have your answer!
9/12+4/12=13/12
You can't reduce, so 13/12 is your answer.
Hope it helps!
-Lacy

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4 years ago

Sherry swam the length of the community pool 4 times. The pool is 32 feet long. What is the total distance Sherry swam, measur

andriy [413]

32 x4 = 128 ft

128 x 12 = 1536

Final Answer: 1,536 inches

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Basile [38]

Answer:

Step-by-step explanation:

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Ahmad wants to paint a rectangular region of a wall with one layer of paint. He has 32 ft of tape to tape around the border of t

Sonbull [250]

Answer:

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3 years ago

the letters of the word independent are written on individual card and the cards are put into a box a card is selected and then

puteri [66]

Answer:

<em>The probability of obtaining the letter p twice is 1/121</em>

Step-by-step explanation:

<u>Probability of Recurring Events</u>

There are 11 letters in the word 'independent', one of which is the letter 'p'.

When those letters are written on individual cards and they are put into a box, there are 11 different choices to pick at random.

This means the individual probability of getting a 'p' is:

$\displaystyle P_1=\frac{1}{11}$

The card is reinserted into the box, leaving the sample space unaltered, thus the second card has the same probability:

$\displaystyle P_2=\frac{1}{11}$

We'll use the multiplication rule. Just multiply the probability of the first event by the second.

$\displaystyle P=P_1*P_2=\frac{1}{11}*\frac{1}{11}$

$\displaystyle P=\frac{1}{121}$

The probability of obtaining the letter p twice is 1/121

6 0

3 years ago