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Wewaii [24]
4 years ago
8

If the length of each side of a cube is doubled, is the surface area doubled? Use an example to support your answer

Mathematics
1 answer:
sashaice [31]4 years ago
4 0
If a = 6l^2 is the total area of the surface of a cube with sides l length and A = 6 (2l)^2 is that area with 2l sides, then we take the ratio A/a = 6 (2l)^2/(6 l^2) = (2l)^2/l^2 = 4l^2/l^2 = 4. So that A = 4a. And that explicitly shows that the area A with 2l for sides is 4 X a, where a is the area when l is the side length. 

<span>Using ratios to compare values of the same thing is the smart way to solve this kind of problem, because many of the values, like the 6 in both, cancel out. In fact, because we found that A/a = (2l/l)^2 we say in general that the area of a cube varies with the square of the length of its side.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
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Answer:

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Step-by-step explanation:

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Make y the subject of these equations.<br> by² = d<br> Jay = 6<br> ay - cy = d.<br> cy - b) = y
allsm [11]

Answer:

See all the answers  below.

Step-by-step explanation:

by² = d

Jay = 6

ay - cy = d.

cy - b) = y

Option A

by² = d

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y² = d/b

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y=√d/b

Option B

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y= 6/Ja

Option C

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Option D

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6 0
3 years ago
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Step-by-step explanatiobn:

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3 years ago
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PLEASE someone help me on this<br> I would appreciate it.
Anton [14]
2x-y =3
multiply by 4
8x - 4y = 12
3x +4y = 10 (unchanged equation)
------------------add
11x = 22

answer is A. the first.
first equation multiplied by 4 then sum to get 11x = 22

3 0
4 years ago
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