Cos(theta) has positive values in quadrants I and IV and it has negative value in quadrants II and III. To know that you don't have to remember this but to imagine xy coordinate system. In it you draw a circle around the center.
Once you do that for any given angle you project the point which represents crossing of side that defines angle and circle. Now project that dot on x-axis. If projection is on positive side of x-axis, cos of that angle is positive and if it is on negative side it is negative.
Answer:
Option 3
Step-by-step explanation:
![{2}^{ \frac{4}{3} } = \sqrt[3]{ {2}^{4} } = \sqrt[3]{16}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7B2%7D%5E%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B16%7D%20)
If the point is at (-3, -4), it is located in the third quadrant. You can find the tangent of an angle by finding the ratio of the length of the opposite side to the length of the adjacent side. In this case, the opposite side of the angle is the vertical line with a length of 4 units, while the adjacent side of the angle is the horizontal line with a length of 3 units. <em>Thus, tan θ = 4/3.</em>
Answer:
x = -4, y = 9
or
(-4, 9)
Step-by-step explanation:
x - 5y = -49
y = -2x + 1
substitute y for -2x + 1
x - 5(-2x + 1) = -49
x + 10x - 5 = - 49
add 5 to both sides
x + 10x - 5 + 5 = - 49 + 5
x + 10x = -44
11x = -44
divide both sides by 11
11x/11 = -44/11
x = -4
substitute x for -4 in any of the original equations
y = -2x + 1
y = -2 * -4 + 1
y = 8 + 1
y = 9
