3 years ago

PLz solve this i need this quick.

1 answer:

5 0

Im not sure but I think its C

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il63 [147K]

Answer:

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Step-by-step explanation:

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3 years ago

IrinaVladis [17]

The first statement is true.

The second statement is false.

The third statement is true.

4 0

3 years ago

Airida [17]

Answer:

Sin A = $\frac{opposite}{hypotenuse} =\frac{32}{40} =\frac{4(8)}{5(8)} =\frac{4}{5}$
Cos C = $\frac{adjacent}{hypotenuse} =\frac{16}{34}=\frac{2(8)}{2(17)} =\frac{8}{17}$
Tan A = $\frac{opposite}{adjacent} =\frac{21}{20}$

8 0

3 years ago

Arturiano [62]

Answer:

$AS = 10\sqrt{41} \\WE = 20\\EN = 25\\Part D = 90 - 10\sqrt{41}$

Step-by-step explanation:

AR = 50

AW = WR = EN = 25

RS = 40

RN = NS = WE = 20

$AS=\sqrt{(AR)^2+(RS)^2}\\AS=\sqrt{(50)^2+(40)^2} \\AS=\sqrt{2500+1600} \\AS=\sqrt{4100} \\AS=\sqrt{41*100}\\AS = 10\sqrt{41}$

$AR + RS - AS = 50 + 40 - 10\sqrt{41} \\AR + RS - AS = 90 - 10\sqrt{41}\\AR + RS - AS = 10 (9 - \sqrt{41})$

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3 years ago

Nostrana [21]

459 + 237 + 115 = 801

4 0

3 years ago