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3 years ago

How can you write the expression 7(b-2) in words?

Mathematics

1 answer:

Karolina [17]3 years ago

6 0

E. The product of 7 and the difference of b - 2 :^)

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Will give brainliest

mariarad [96]

Answer:

8/27

Step-by-step explanation:

6 0

3 years ago

11. Find the sum of the arithmetic series. overset [22] underset{k=1}\huge{Sigma) (-4k - 13) =

sergiy2304 [10]

Answer:

okay, we need to add up for all k=1 till k=22

we could do it like this

(-4*1 -13) + (-4*2 -13) + (-4*3 -13) + ...

but this is long and boring, so we need another valid, yet vastly faster method to calculate this sum

we know that the "-13" part will occur 22 times, so let's write this component as "-13*22"

the -4k gents bigger with each step, k will take all the natural numbers from 1 to 22

so we could write

"-4 * (1+2+3+4+5+6+7...+21+22l

alot simpler and faster, but not fast enough

let's add up all numbers from 1 to 22 into one number

1 + 22 = 23

2 + 21 = 23

3 + 20 = 23

...

this works eleven times (bc we use up 2 numbers in each step), so the numbers from 1 to 22 added up are just

23*11= 230+23 = 252

now let's construct the final calculation

-4 * 252 -13*22 = -1294

there's your sum.

hope it helps you overall.

brainliest would be very kind ic some else leaves an answer, may it be just a greeting

4 0

3 years ago

Find numbers between -.27 and -.28

Ede4ka [16]

Answer:

that is literally so easy just add some type of fraction

Step-by-step explanation:

-.27 1/10

-.27 2/10

-.27 3/10

etc.

8 0

3 years ago

F:[1/2,infinity)—>[3/4,infinity) <br> f(x)=x^2-x+1 <br> find the inverse of f(x);please explain

dexar [7]

Answer:

$f^{-1}(x)=\frac{1}{2}+\sqrt{x-\frac{3}{4}}$

Step-by-step explanation:

y=x^2-x+1

We want to solve for x.

I'm going to use completing the square.

Subtract 1 on both sides:

y-1=x^2-x

Add (-1/2)^2 on both sides:

y-1+(-1/2)^2=x^2-x+(-1/2)^2

This allows me to write the right hand side as a square.

y-1+1/4=(x-1/2)^2

y-3/4=(x-1/2)^2

Now remember we are solving for x so now we square root both sides:

$\pm \sqrt{y-3/4}=x-1/2$

The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.

This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.

That is we want:

$\sqrt{y-3/4}=x-1/2$

Add 1/2 on both sides:

$1/2+\sqrt{y-3/4}=x$

The last step is to switch x and y:

$1/2+\sqrt{x-3/4}=y$

$y=1/2+\sqrt{x-3/4}$

$f^{-1}(x)=1/2+\sqrt{x-3/4}$

8 0

3 years ago

What is the following product?<br> 3 square root of 5 • square root of 2

evablogger [386]

The answer is 6√200, or on edge.

5 0

3 years ago