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Dvinal [7]
3 years ago
6

How can you write the expression 7(b-2) in words?

Mathematics
1 answer:
Karolina [17]3 years ago
6 0
E. The product of 7 and the difference of b - 2 :^)
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Mr. smith had four daughters Each daughter had 4 kids how many kids did me.smith have
erik [133]

Easy! If Smith had four daughters who each had 4 kids, then he had a total of 20 kids. I got this by multiplying the daughters by their kids, 4x4, and adding the four daughters, so it equals 20 kids in total!

Hope it helps!

6 0
3 years ago
Read 2 more answers
Ariel swims 2 1/6 miles in every 1/3 hour. Enter the number of miles Ariel swims in 1 minute.
weqwewe [10]

In order to find the distance covered in 1 minute, we need to divide distance covered 2 1/6 miles by 20 minutes.We are given : Ariel swims 2 1/6 miles in every 1/3 hour.

Let us convert 1/3 hour into minutes.

There are 60 minutes in an hour.

Therefore, 1/3 hours = 60 × 1/3 = 20 minutes.

So, we could say, "Ariel swims 2 1/6 miles in every 20 minutes".


2 1/6÷ 20 = 13/6 ÷ 20.

Let us convert division sign into multiplication and flip 20 to 1/20.

We get

<h3>13/6 × 1/20 = 13/120 miles in 1 minute.</h3><h3>In decimal 0.11 mile in 1 minute.</h3>
4 0
3 years ago
I need help asap<br> I cannot figure this out
tankabanditka [31]
The answer is A :)))
3 0
2 years ago
How many grams are 2.7x10-^4 grams
andrew-mc [135]

Answer:

0,00027 grams!

Step-by-step explanation:

This is a scientific notation problem.

When a number is followed by a 10^{-1}, it means that said number has one zero at the beginning.

In this case, the number is followed by 10^{-4}, so that means that 2.7 has four zeros at the beginning. So, 2.7x10^{-4} grams is equal to 0,00027 grams! (always the comma goes after the first zero).

6 0
4 years ago
Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0
skad [1K]
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\bf 6rsin(\theta)\iff 2\cdot r\cdot  \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}&#10;\\\\\\&#10;\textit{now, bear in mind we're just borrowing from zero, 0}&#10;\\\\&#10;\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}

\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\&#10;\left. \qquad  \right.\uparrow \\&#10;\textit{so-called "completing the square"}&#10;\\\\\\\&#10;[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)&#10;\\\\\\&#10;r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)
3 0
3 years ago
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