A power supply unit (or PSU) converts mains AC to low-voltage regulated DCpower for the internal components of acomputer. ... Some power supplies have a manual switch for selecting input voltage, while others automatically adapt to the mains voltage.
Use the function varimp() on the output of train() and save it to an object called imp object.
<h3>What is the classification that has More than Two Classes and the Caret Package</h3>
In the Classification that has More than Two Classes and the Caret Package section, one need to use the methods that can be able to adapt to higher forms or dimensions and through a lot of different machine learning algorithms.
Note that varImp is seen as a generic method for calculating variable .
Hence, Use the function varimp() on the output of train() and save it to an object called imp object.
Learn more about Computer function from
brainly.com/question/17048576
#SPJ1
Out door air pollution has been a problem since ancient Romans...but the industrial revouloution was when outdoor air pollution increased and it a significant problem...
hope this helps
Answer:
Explanation:
Since all of the items in the array would be integers sorting them would not be a problem regardless of the difference in integers. O(n) time would be impossible unless the array is already sorted, otherwise, the best runtime we can hope for would be such a method like the one below with a runtime of O(n^2)
static void sortingMethod(int arr[], int n)
{
int x, y, temp;
boolean swapped;
for (x = 0; x < n - 1; x++)
{
swapped = false;
for (y = 0; y < n - x - 1; y++)
{
if (arr[y] > arr[y + 1])
{
temp = arr[y];
arr[y] = arr[y + 1];
arr[y + 1] = temp;
swapped = true;
}
}
if (swapped == false)
break;
}
}
Answer:
The codes below implement the problem statements
Explanation:
public class Percentages {
public static void computePercent (int a,int b)
{
System.out.println(a+" is "+(a*100/b)+"% of "+b);
}
public static void main(String []args)
{
int a=2;
int b=5;
computePercent(a,b);
computePercent(b,a);
}
}
<u>
</u>
<u>Part(b)
</u>
import java.util.*;
public class Percentages {
public static void computePercent (int a,int b)
{
System.out.println(a+" is "+(a*100/b)+"% of "+b);
}
public static void main(String []args)
{
Scanner s= new Scanner(System.in);
int a=s.nextInt();
int b=s.nextInt();
computePercent(a,b);
computePercent(b,a);
}
}
