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3 years ago

Why do TV shows/Movies from the 90's and early 2000s look so much different compared to today?

1 answer:

7 0

Back then, movies were black and white because they had cameras that could only see black and white. In the late 1900's and early 2000's, they developed color cameras. But the common resolution and screen size was 640x480 or 4:3. Nowadays, in the late 2000's and early 2010, the widescreen format was more commonly used for many reasons. Today, the common colors are RGB 1M colors, and the resolution is 16:9. Some movies like to go even farther, like me, and use 21:9,which is super widescreen. That is more immersive than 16:9, and gives the watcher a wider, better experience.

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What does PRAM stand for?

Nana76 [90]

<span>PRAM- Phase-Change Random Access Memory</span>

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3 years ago

Read 2 more answers

The cost of an items is Rs 200. what will be the cost of 50 such items. write a simple program

alexandr402 [8]

Answer:

In Python:

Unit_Cost = 200

Cost50 = 50 * Unit_Cost

print("Cost of 50 items: Rs."+str(Cost50))

Explanation:

This initializes the unit cost to 200

Unit_Cost = 200

This calculates the cost of 50 of such items

Cost50 = 50 * Unit_Cost

This prints the calculated cost

print("Cost of 50 items: Rs."+str(Cost50))

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2 years ago

Suppose you are working on a team using object-oriented programming, and your supervisor observes you creating new objects. She

o-na [289]

The correct way to observe and create something

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2 years ago

What is your favorite coler and what do you like to do and

KIM [24]

Answer:

Orange

Explanation:

I like orange because its vibrant.

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3 years ago

The router can deliver packets directly over interfaces 0 and 1 or it can forward packets to Routers R2, R3, or R4. Describe wha

ra1l [238]

Answer:

Following are the solution to this question:

Explanation:

In point A:

It applies the AND operation with the subnet-mask that is

$=128.96.39.00001010 \ \ AND \ \ 255.255.255.10000000 \\\\= 128.96.39.0000000 \\\\= 128.96.39.0 \\\$

This corresponds to a 128.96.39.0 subnet. This is why the router sent the packet to 0.

In point B:

It applies the AND operation with the subnet-mask that is $255.255.255.128$

$= 128.96.40.00001100\ AND \ 255.255.255.10000000 \\\\ = 128.96.40.0000000\\\\= 128.96.40.0$

This suits the 128.96.40.0 subnet. The router then sent R2 to the packet. The packet.

In point C:

It applies the AND operation with the subnet-mask that is $255.255.255.128$

$=128.96.40.10010111 \ AND \ 255.255.255.10000000 \\\\= 128.96.40.1000000\\\\= 128.96.40.128$

It applies the AND operation with the subnet-mask that is $255.255.255.192$

$= 128.96.40.10010111 \ AND \ 255.255.255.11000000 \\\\= 128.96.40.1000000 \\\\= 128.96.40.128\\$

All of the matches of its sublinks above.

Its default R4 router was therefore sent to the router by router.

In point D:

It applies the AND operation with the subnet-mask that is $255.255.255.192$

$= 192.4.153.00010001 \ AND \ 255.255.255.11000000\\\\ = 192.4.153.0000000 \\\\= 192.4.153.0 \\\\$

It matches the 192.4.153.0 subnet. It router has sent packet to R3 then.

In point E:

It applies the AND operation with the subnet-mask that is $255.255.255.128$

$= 192.4.153.01011010\ AND \ 255.255.255.10000000 \\\\= 192.4.153.0000000 \\\\= 192.4.153.0$

There, neither of the subnet inputs correlate with the ip address with the same subnet mask.

It applies the AND operation with the subnet-mask that is $255.255.255.192$

$=192.4.153.01011010\ AND \ 255.255.255.11000000 \\\\ = 192.4.153.0100000 \\\\= 192.4.153.64$

It does not correlate to the subnet entries for same subnet mask, and therefore neither of the entries matches their corresponding ip address entries.

Mask of the subnet. That packet would therefore be sent to the default R4 router by the router.

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2 years ago