Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
Answer:
A
Step-by-step explanation:
Domain here is where arrows begin. So, domain of this function is {4,5,6,8,9}.
Answer : A.
Answer:
29/12 > x
Step-by-step explanation:
–3(x + 2) > 4x + 5(x – 7)
Distribute
-3x -6 > 4x +5x-35
Combine like terms
-3x-6 > 9x -35
Add 3x to each side
-3x+3x-6 > 9x+3x -35
-6 > 12x-35
Add 35 to each side
-6+35 > 12x -35+35
29 > 12x
Divide each side by 12
29/12 > 12x/12
29/12 > x
Answer: lalalallalalalalal
Step-by-step explanation:
