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alexandr402 [8]
3 years ago
14

Evaluate 4 + (-2) - (-3) – 6.

Mathematics
2 answers:
fgiga [73]3 years ago
8 0

Answer:

Step-by-step explanation:

-1

Zinaida [17]3 years ago
8 0

Answer:

Your answer would be -1

~hope this helped~

Step-by-step explanation:

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A cone has a volume of 226.08 cubic millimeters and a height of 6 millimeters. What is its
dezoksy [38]

Answer:

r≈5.36656314

Step-by-step explanation:

Since A=πr(r+\sqrt{h^2+r^2}) so we get that 226.08/pi≈72 or 226.08/3.14=72 we then plug it in to get 72=r(r+\sqrt{36+r^2}) so we get r≈5.36656314

6 0
3 years ago
Read 2 more answers
Determine the larger of two consecutive integers whose sum add to 85
Vesnalui [34]
N+(n+1) = 85. 2n+1=85, 2n=84. n=42. So the consecutive integers are 42 and 43, and the larger one is 43.
8 0
3 years ago
The mean number of hours of study time per week for a sample of 562 students is 23. If the margin of error for the population me
Vadim26 [7]

Answer:

The 98% confidence interval for the mean number of hours of study time per week for all students is (20.9, 25.1).

Step-by-step explanation:

Confidence interval:

Sample mean plus/minus the margin of error.

In this question:

Mean of 23.

Margin of error 2.1.

Then

23 - 2.1 = 20.9

23 + 2.1 = 25.1

The 98% confidence interval for the mean number of hours of study time per week for all students is (20.9, 25.1).

3 0
2 years ago
A box designer has been charged with the task of determining the surface area of various open boxes (no lid) that can be constru
Viktor [21]

Answer:

1) S = 2\cdot w\cdot l - 8\cdot x^{2}, 2) The domain of S is 0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}. The range of S is 0 \leq S \leq 2\cdot w \cdot l, 3) S = 176\,in^{2}, 4) x \approx 4.528\,in, 5) S = 164.830\,in^{2}

Step-by-step explanation:

1) The function of the box is:

S = 2\cdot (w - 2\cdot x)\cdot x + 2\cdot (l-2\cdot x)\cdot x +(w-2\cdot x)\cdot (l-2\cdot x)

S = 2\cdot w\cdot x - 4\cdot x^{2} + 2\cdot l\cdot x - 4\cdot x^{2} + w\cdot l -2\cdot (l + w)\cdot x + l\cdot w

S = 2\cdot (w+l)\cdot x - 8\cdpt x^{2} + 2\cdot w \cdot l - 2\cdot (l+w)\cdot x

S = 2\cdot w\cdot l - 8\cdot x^{2}

2) The maximum cutout is:

2\cdot w \cdot l - 8\cdot x^{2} = 0

w\cdot l - 4\cdot x^{2} = 0

4\cdot x^{2} = w\cdot l

x = \frac{\sqrt{w\cdot l}}{2}

The domain of S is 0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}. The range of S is 0 \leq S \leq 2\cdot w \cdot l

3) The surface area when a 1'' x 1'' square is cut out is:

S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1\,in)^{2}

S = 176\,in^{2}

4) The size is found by solving the following second-order polynomial:

20\,in^{2} = 2 \cdot (8\,in)\cdot (11.5\,in)-8\cdot x^{2}

20\,in^{2} = 184\,in^{2} - 8\cdot x^{2}

8\cdot x^{2} - 164\,in^{2} = 0

x \approx 4.528\,in

5) The equation of the box volume is:

V = (w-2\cdot x)\cdot (l-2\cdot x) \cdot x

V = [w\cdot l -2\cdot (w+l)\cdot x + 4\cdot x^{2}]\cdot x

V = w\cdot l \cdot x - 2\cdot (w+l)\cdot x^{2} + 4\cdot x^{3}

V = (8\,in)\cdot (11.5\,in)\cdot x - 2\cdot (19.5\,in)\cdot x^{2} + 4\cdot x^{3}

V = (92\,in^{2})\cdot x - (39\,in)\cdot x^{2} + 4\cdot x^{3}

The first derivative of the function is:

V' = 92\,in^{2} - (78\,in)\cdot x + 12\cdot x^{2}

The critical points are determined by equalizing the derivative to zero:

12\cdot x^{2}-(78\,in)\cdot x + 92\,in^{2} = 0

x_{1} \approx 4.952\,in

x_{2}\approx 1.548\,in

The second derivative is found afterwards:

V'' = 24\cdot x - 78\,in

After evaluating each critical point, it follows that x_{1} is an absolute minimum and x_{2} is an absolute maximum. Hence, the value of the cutoff so that volume is maximized is:

x \approx 1.548\,in

The surface area of the box is:

S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1.548\,in)^{2}

S = 164.830\,in^{2}

4 0
3 years ago
Find the common difference for the arithmetic sequence. 1.7, 2.7, 3.7 4.7.....
Anni [7]

Answer:

Step-by-step explanation:

You do not need to where the formula comes from but, just for fun, here’s a hint

To add up the numbers 1 to 10

Write out the numbers

1 2 3 4 5 6 7 8 9 10

Write them backwards

10 9 8 7 6 5 4 3 2 1

Add up both lists

11  11  11  11  11  11  11  11  11 11

This is 10 × 11 = 110

But this is twice the sum as two lots were added together

So the sum of the numbers 1 to 10 is 110 ÷ 2 = 55

 

ArSeqSum Notes fig4, downloadable IGCSE & GCSE Maths revision notes

5 0
3 years ago
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