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ycow [4]
4 years ago
14

A graph is given below. Answer the following questions based off the graph:

Mathematics
1 answer:
Tcecarenko [31]4 years ago
6 0

(a) The slope of the graph is \frac{2}{5}

(b) The equation of the line in point-slope form is y - 1 = \frac{2}{5} (x + 2.5)

(c) The y-intercept of the graph is (0 , 2)

(d) The y-intercept is correct

(e) We substitute x by zero because the line intersects y-axis at a point

its x-coordinate must be zero. Then we calculate the value of

y-coordinate when x = 0. The y-coordinate = 2, so the

y-intercept is (0 , 2)

Step-by-step explanation:

The slope of a line whose endpoints are (x_{1},y_{1}) and (x_{2},y_{2})

is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

The equation of a line in a point-slope form is:

y-y_{1}=m(x-x_{1})

From the graph:

1. The line passes through points (-5 , 0) and (0 , 2)

2. Substitute these points in the rule of the slope to find it

3. Writ the equation of the line in the form of point-slope

(a)

∵ (x_{1},y_{1}) = (-5 , 0)

∵ (x_{2},y_{2}) = (0 , 2)

∴ m=\frac{(2-0)}{(0--5)}=\frac{2}{5}

The slope of the graph is \frac{2}{5}

(b)

∵ Point (-2.5 , 1) lies on the line

∴ (x_{1},y_{1}) = (-2.5 , 1)

∵ The point-slope form is ⇒ y-y_{1}=m(x-x_{1})

∵ m = \frac{2}{5}

- Substitute the coordinates of the point and the slope in the equation

∴ y - 1 = \frac{2}{5} (x - -2.5)

∴ y - 1 = \frac{2}{5} (x + 2.5)

The equation of the line in point-slope form is y - 1 = \frac{2}{5} (x + 2.5)

(c)

When the line intersects the y-axis at point (0 , b), then b is the

y-intercept

∵ The line intersects y-axis at point (0 , 2)

∴ The y-intercept is (0 , 2)

The y-intercept of the graph is (0 , 2)

(d)

Let us substitute x in the equation by zero

∵ x = 0

∵ The point slope form of the equation is y - 1 = \frac{2}{5} (x + 2.5)

∴ y - 1 = \frac{2}{5} (0 + 2.5)

∴ y - 1 = \frac{2}{5} (2.5)

∴ y - 1 = 1

- Add 1 to both sides

∴ y = 2

- When x = 0 then y = 2

∴ Point (0 , 2) is the y-intercept

The y-intercept is correct

(e)

We substitute x by zero because the line intersects y-axis at a point its

x-coordinate must be zero

Then we calculate the value of y-coordinate when x = 0

The y-coordinate = 2, so the y intercept is (0 , 2)

Learn more:

You can learn more about linear equation in brainly.com/question/13168205

#LearnwithBrainly

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Let's expand (2x² - 3)² to give ;

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6x^(5)-18x⁴-(27/2)x³

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We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

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______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

We now subtract the new multiplied term beneath the immediate one from the immediate one to get;

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______________________

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6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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