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3 years ago

Which equation best represents the situation described??

Mathematics

2 answers:

disa [49]3 years ago

7 0

I think the answer to this is d hope it helps

spayn [35]3 years ago

7 0

The answer is going to be A, believe me I'm in college

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Koto’s average velocity along her route was 4. 5 m/s. She started at her house and traveled 15,000 meters north, 5,000 meters ea

Lostsunrise [7]

The time taken for her trip is 3 hours.

<h3>Given that</h3>

Koto’s average velocity along her route was 4. 5 m/s.

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3>We have to determine</h3>

What was the time of her trip?

<h3>According to the question</h3>

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3 /><h3>The calculation of such a trip of Koto can be done by applying the known formula of Time when the Speed is multiplied by Distance to compute the actual time of the trip.</h3>

The formula to calculate the time for her trip is;

$\rm Speed = \dfrac{ Distance}{Time}\\
\\
Time = \dfrac{Distance}{Speed}\\
\\
$

Using the formula above, the commute in each direction is added as 45000 meters or 45 kilometers.

If Koto's average speed is 4.5 meters per second, then she travels roughly 270 meters in one minute.

Substitute all the values in the formula;

$\rm\ Time = \dfrac{Distance}{Speed}\\\\ Time = \dfrac{45000}{270}\\
\\
Time =166.7$

Converting minutes into hours,

$\rm Hours = \dfrac{Minute}{60}\\
\\
Hours = \dfrac{166.7}{60}\\
\\
Hours = 2.77 \\
\\
= 3\ hours$

Hence, the time taken for her trip is 3 hours.

To know more about Time and Distance click the link given below.

brainly.com/question/4433818

5 0

2 years ago

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su

Paul [167]

Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

$y=2-x^2$

the parabola is open down with vertex at (0,2)

We can find that the rectangle also will be symmetrical about y axis.

Let the vertices on x axis by (p,0) and (-p,0)

Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation

Now width = $2-p^2$

Area = l*w = $2(2p-p^3)$

Use derivative test

I derivative = $2(2-3p^2)$

II derivative = $-12p$

Equate I derivative to 0 and consider positive value only since we want maximum

p = $\sqrt{\frac{2}{3} }$

Thus width= $\sqrt{\frac{2}{3} }$

Length = $2\sqrt{\frac{2}{3} }$

Width = $2-2/3 = 4/3$

3 0

3 years ago

Neo is making invitations for their birthday party.

VMariaS [17]

Answer:

15%

Step-by-step explanation:

40=100%

20=50%

4=10%

2=5%

10%+5%=15%

4+2=6

6 0

2 years ago

4 times the quantity - 16 plus a number

Kisachek [45]

Answer:

4x{16+y}=?

Step-by-step explanation:

4 0

3 years ago

Which illustrates the construction of a perpendicular to a line from a point on the line?

quester [9]

I believe the correct answer from the choices listed above is the last option. The last option clearly describes the illustration of the construction of a perpendicular to a line from a point on the line where you start on a point in the line. Using an arbitrary radius, draw arcs intersecting the line <span> at two points. </span>
Hope this answers the question. Have a nice day.

6 0

2 years ago

Read 2 more answers