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Aleksandr-060686 [28]

3 years ago

12

Formula for "18 is 32% of what number w?"

1 answer:

beks73 [17]3 years ago

3 0

23.76 I'm not 100% sure but I think (sorry if it's wrong!)

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An electronics company has developed a new hand held device. The company predicts that the start up cost to manufacture the new

alex41 [277]

Profit = revenue - expenses

expenses : 125,000 + 6.50x
revenue : 9x
so to make a profit, ur revenue (income) has to be higher then ur expenses

revenue > expenses
A. ) 9x > 125,000 + 6.50x
9x - 6.50x > 125,000
2.5x > 125,000
x > 125,000 / 2.5
x > 50,000......so they would have to sell at least 50,001 devices to make a profit <==

B.) the cost of making 1 device is 10% more then the company predicted....10% more then 6.50.....6.50(1.10) = 7.15.....this is the new cost of making 1 device <==

9x > 125,000 + 7.15x ....this is the inequality with the 10% more added
9x - 7.15x > 125,000
1.85x > 125,000
x > 125,000 / 1.85
x > 67,567.5......so to make a profit, they would have to sell at least 67,568 devices to make a profit <==

7 0

3 years ago

87-(36.5-11.5)*(-3)+9 simplify using order of operations

OLga [1]

Remember PEMDAS
Do parentheses, results in 25. So whats left is 87-25*(-3)+9
Then you multiply -25 by -3, answer is 75. 87+75+9
Add all of them up. 171
The answer is 171!

5 0

3 years ago

Read 2 more answers

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

8 0

3 years ago

Solve this equation for k.<br><br> 3 − 3k + 7k = 5b<br><br> Enter the correct answer in the box.

Sloan [31]

Answer:

k=5b/4−3/4

Step-by-step explanation:

3-3k+7k=5b

Isolate the variable by dividing each side by factors that don't contain the variable.

k=5b/4−3/4

-hope it helps

8 0

2 years ago

Find the area of the shaded region. Use 3.14 for π.

Lina20 [59]

I hope this helps you

small circle area=3,14.19^2=1133,5

large circle area =3,14.24^2=1808,6

shaded area=1808,6-1133,5

shaded area=675,1

6 0

3 years ago