Answer:
Bob's typing speed is 39 words per minute.
Bill's typing speed is 58 words per minute.
Step-by-step explanation:
<u>Given : </u>
Bill can type 19 words per minute faster than bob. their combined typing speed is 97 words per minute.
<u>To Find : </u>
Bobs typing speed
<u>Solution : </u>
Let the bobs typing speed is x
According to the given question :
Bobs typing speed is x
Bill's typing speed is 19+x
Their combined speed is 97 words per minute.
<u>Solving value x : </u>
x + 19+x = 97
2x + 19 = 97
2x = 97 - 19
2x = 78
x = 78/2
x = 39
Bobs typing speed = 39
Bill's typing speed 39 + 19 = 58
Hence, Bobs speed is 39 words per minute.
Answer: 23.94 cm
Step-by-step explanation: I am totally not sure if this is the answer, but think of it this way: Those are 2 semi circles. The formula for the area of a semi circle is A = π * r^2 / 2. For the semi circle with 6 cm, the radius is 3. So we can plug it in the formula. 3.14 * 3^2 / 2, which is 14.13. For the semi circle with 5 cm, the radius is 2.5. Again plug it in and it will be 3.14 * 2.5^2 / 2, which is 9.8125. Then, to get the total area, add the 2 final values together. 9.8125 + 14.13, which is 23.9425. Then it said "round to the nearest hundredth if necessary. We can round to the nearest hundredth, which is 23.94, so that would be the answer. That is just my thought process.
I am not really sure if it's the answer, but take a gander at my thought process and hopefully, you can agree with me.
Answer:
The factored expression is 2(x² + 5)(x + 3).
Step-by-step explanation:
Hey there!
We can use a factoring technique referred to as "grouping" to solve this problem.
Grouping is used for polynomials with four terms as a quick and easy factoring method to remove the GCF and get down to the initial terms that create the expression/function.
Grouping works in the following matter:
- Given equation: ax³ + bx² + cx + d
- Group a & b, c & d: (ax³ + bx²) + (cx + d)
- Pull GCFs and factors
Let's apply these steps to the given equation.
- Given equation: 2x³ + 6x² + 10x + 30
- Group a & b, c & d: (2x³ + 6x²) + (10x + 30)
- Pull GCFs and factors: 2x²(x + 3) + 10(x + 3)
As you'll see, we have a common term with both sides of the expression. This term, (x + 3), is a valuable asset to the factoring process. This is one of the factors for our expression.
Now, we use our GCFs to create another factor.
- List GCFs: 2x², 10
- Create a term: (2x² + 10)
Finally, we'll need to simplify this one by taking another GCF, 2.
- Pull GCF: 2(x² + 5)
Now that we have this term, we need to understand that this <em>could</em> also be factored further using imaginary numbers, but it is also acceptable to leave it in this form.
Therefore, we have our final factors: 2(x² + 5) and (x + 3).
However, when we factor, we place all of our terms together. This leaves us with the final answer: 2(x² + 5)(x + 3).
137 because it’s the same as the angle given.
Answer:
2, 4, 8, 16, 32
Step-by-step explanation: