5) The height of a rocket after it is launched
For this case, what you should do is remember the kinematics expressions where we have:
a
v = a * t + vo
y = a * t ^ 2 + vo * t + i
Where,
a: acceleration
v: speed
y: vertical position
t: time
vo: initial speed
yo: initial position
We observe that the expression for the given position is given by a quadratic expression.
Answer:
a?
Step-by-step explanation:
Length (L): L
width (w): (2/3)L
Perimeter (P) = 2L + 2w
390 = 2(L) + 2(2/3)(L)
1170 = 6L + 4L
1170 = 10L
117 = L
width (w): (2/3)L = (2/3)(117) = 2(39) = 78
Answer: width = 78 ft, length = 117 ft
Can you please please give me more information please thank you
