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3 years ago

The ordered pair (0,4) is a solution of which system?

Mathematics

2 answers:

Helga [31]3 years ago

7 0

C
when x=0 and y=4, 0+5=5 on the right, y=4 on the left, 4 is smaller than 5, and y=4 satisfies y≥4

hichkok12 [17]3 years ago

3 0

Answer:

y<x+5

Step-by-step explanation:

The ordered pair (0,4) is a solution

We check with each inequality, and find which inequalities makes it true

(a) y<=4

y>=x+5

Lets plug in x=0 and y=4

4<=4 its true

4 >=0+5 ---> 4>=5 its false

Both inequalities does not satisfies

(b) y<4

y<x+5

Lets plug in x=0 and y=4

4<4 its false

4 <0+5 ---> 4<5 its true

Both inequalities does not satisfies

y<x+5

Lets plug in x=0 and y=4

4>=4 its true

4 <0+5 ---> 4<5 its True

Both inequalities satisfies

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3 years ago

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AVprozaik [17]

Answer:

$\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}$

Step-by-step explanation:

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$x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D$

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3 years ago

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GrogVix [38]

You are going to subtract.
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3 years ago

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AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

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So, this integral is divergent.

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So, this integral is divergent.

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3 years ago