I understand some of this but this ones got me stumped i tried pemdas but im still lost

Mathematics

1 answer:

Mandarinka [93]3 years ago

6 0

Just replace $x$ with its given value:

$9x^{2}-4x-3~~~~\text{where }x=-2\\ \\ \\ 9\cdot (-2)^{2}-4\cdot (-2)-3\\ \\ =9\cdot 4+8-3\\ \\ =36+8-3\\ \\ =41$

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Roll two fair dice. Each die has six faces. A. Let A be the event that either a 3 or 4 is rolled first followed by an odd number

zhenek [66]

Answer:

A. 0.16

B. 0.58

C. No

D. Dependent

Step-by-step explanation:

The sampling space has 36 outcomes.

The event A has 6 outcomes (3,1), (3,3), (3,5), (4,1), (4,3),(4,5)

So P(A)= 6/36 = 0.16

The table in the picture shows the 15 outcomes that are not allowed, so there are 36-15 = 21 possible outcomes for B and its probability is 21/36 = 0.58

Are A and B mutually exclusive events?

No since their intersection is not empty, for example (3,1) belongs to both A and B

In order for A and B to be independent, it must happen that

P(A∩B)=P(A)P(B)

A∩B={(3,1),(3,3),(4,1)} so P(A∩B) = 3/36

whereas

P(A)P(B) = (6/36)(21/36) = (1/6)(7/12)=7/72

So A and B are not independent.