720 pt/h= ? qt/min please show step by step
1 answer:
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1)
f(x) = x² + 9 g(x) = 24 + 4x
f(4) = (4)² + 9 g(-1) = 24 + 4(-1)
= 16 + 9 = 24 - 4
= 25 = 20
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g(x) = 2ˣ - 4 f(x) = 4x² - 5x - 5
g(6) = 2⁶ - 4 f(-5) = 4(-5)² - 5(-5) - 5
= 64 - 4 = 100 + 25 - 5
= 60 = 120
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f(x) = (3x + 7)²
f(1) = (3(1) + 7)²
= (3 + 7)²
= (10)²
= 100
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3xy + 2x² - y³ ; when x = 6 and y = -2
3(6)(-2) + 2(6)² - (-2)³
-36 + 72 - (-8)
36 + 8
44
Answer
given,
thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
X = U[0.95,1.05] 0.95≤ x ≤ 1.05
the cumulative distribution function of flange
F(x) = P{X≤ x}=
=
b) P(X>1.02)= 1 - P(X≤1.02)
=
= 0.3
c) The thickness greater than 0.96 exceeded by 90% of the flanges.
d) mean =
= 1
variance =
= 0.000833