Answer:
The length of the rope between the boat and the dock is of 30 feet.
Step-by-step explanation:
Given:
tan(40) ≈ 0.839
Angle of depression = 40 (deg)
Distance between boat and the floor of the ocean = 25.17 feet
If we look into the diagram we can see that,they form 2 right angled triangle.
Where we can say that :
Distance between boat and dock = Rope's distance = Base of the triangle.
Let the length of the rope be 'x' feet.
Considering the dotted triangle:
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Length of the rope between the boat and the dock is 'x' = 30 feet.
Answer:
179/180
Step-by-step explanation:
<em><u>Step One</u></em>
Find the prime factors of 18 and 20
18:3*3*2
20: 2 * 2 * 5
<em><u>Step Two</u></em>
You need two 2s two 3s and one 5 for the common denominator
The common denominator is 2 * 2 * 3 * 3 * 5 = 180
<em><u>Step Three</u></em>
Put the two fractions over 180
179/180
Answer:
3) a translation followed by a reflection
Step-by-step explanation:
First, to get to A'B'C'D', we can see that A is still on top, D is on the right, etc. -- everything is just shifted up and to the right. This signifies a translation as it is simply a shift.
Next, to get to A''B''C''D'', we can see that A'' is now on the right. If this would be a rotation from A'B'C'D', we can visualize it as the shape rotating to the right. B'' would then be on top as it is to the left of A' in A'B'C'D', so if B' would be rotated to the right, it would then go to the top of A''. However, B'' is in the bottom, and D'' is on the top, signifying a flip of what the rotation would be. As this is not a simple shift, the only option left is a reflection.
To answer this item, we just have to substitute the given to the equation, where s is equal to 4 and v is equal to 80 ft/s.
4 = (80)t - 0.5(32 ft/s²)(t²)
The value of t from the equation generated above is equal to 4.94 s. Thus, the answer is approximately 5, letter D.
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A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a load of 8.00 kg is hung on its end. Find the stress, the strain, and the Young’s modulus for the material of the wire.
Solution:
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a lo
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prev Statement of a problem № 2618 next
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a load of 8.00 kg is hung on its end. Find the stress, the strain, and the Young’s modulus for the material of the wire.
Solution:
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a lo
main
prev Statement of a problem № 2618 next
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a load of 8.00 kg is hung on its end. Find the stress, the strain, and the Young’s modulus for the material of the wire.
Solution:
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a lo
main
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