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aleksklad [387]
3 years ago
10

Prove that mn < 0 if and only if m > 0 and n < 0 or m < 0 and n > 0

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0
Only one number can but negative for it to be true.

If both positive then product is positive

If both negative then product is also positive

(-1)*(-1)=1
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If a line slope of -1/2 contains the point (2,3), then it must also contain which of the following points?
tiny-mole [99]
Before the fraction: -1/2, i have a negative sign
use y=mx+b
3=-1/2(2)+b
3+1=-1+b+1
4=b
check your work
0=-1/2x+4
0+4=-1/2x
(4)÷(-1/2)=(-1/2x)÷(-1/2)
-2=x
another pair is (-2,0) use this to figure out the other points, and/or the points you have in the multiple choice.
5 0
4 years ago
The contents of a cell in a spreadsheet are shown below. 4.7893541EE-6 What number does the contents of the cell represent?
matrenka [14]

Answer:

D

Step-by-step explanation:

6 0
4 years ago
Rewrite the following equation in standard form.<br> y + 7 = 2(x - 6)
babunello [35]

Answer:

(-5)

Step-by-step explanation:

(-5)+7=2(×-6) fahhshzhsuhshzhhsbwysvavaghahahahwhwgwvavvwhhwshahwh

4 0
3 years ago
Is there any systematic tendency for part-time college faculty to hold their students to different standards than do full-time f
alexandr1967 [171]

Answer:

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

-1. 34

0.1837

Step-by-step explanation:

Full time :

n1 = 125

x1 = 2.7386

s1 = 0.65342

Part time :

n2 = 88

x2 = 2.8439

s2 = 0.49241

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

Test statistic :

The test statistic :

(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]

(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]

−0.1053 / sqrt(0.0034156615712 + 0.0027553)

-0.1053 /0.0785554

= - 1.34

Test statistic = - 1.34

The Pvalue :

Using df = smaller n - 1 = 88 - 1 = 87

Pvalue from test statistic score ;

Pvalue = 0.1837

Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.

At α = 0.01 ; the result is insignificant

6 0
3 years ago
Help on math please!!!
juin [17]

Table:

y = x²

can also be written as: f(x) = x²

Plug in each x value and calculate the output:

f(-4) = (-4)² = 16

f(-3) = (-3)² = 9

f(-2) = 4

f(-1) = 1

f(-\frac{1}{2}) = \frac{1}{4}

f(0) = 0

f(\frac{1}{2}) = \frac{1}{4}

f(1) = 1

f(2) = 4

f(3) = 9

f(4) = 16

Answers:

a) graph shown in picture

b) vertex is at (0, 0)

5 0
3 years ago
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