Wavelength varies inversely with frequency

Mathematics

2 answers:

marissa [1.9K]3 years ago

6 0

Answer:

xy=302,400

Step-by-step explanation:

i just did the problem right now on edge and that's what i got

hope this helps and that I'm not too late

zvonat [6]3 years ago

5 0

Answer:

xy=302,400

Step-by-step explanation:

just trust me this is the answer on edg

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joja [24]

So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root

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$\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}}
\\\\\\
\cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6}
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