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Ann [662]
3 years ago
8

At a school picnic, your teacher asks you to mark a field every 10 yards so students can play football. The teacher accidentally

gave you a meter stick instead of a yardstick. how far apart in meters should you mark the lines if you still want them to be in the right places?
Mathematics
1 answer:
Oxana [17]3 years ago
3 0
Approximately 9 meters are in 10 yards, (as there is approximately 1 meter in a yard, .9144 to be exact.) 
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Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62 cm, what is the percent error of Jocelyn's
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The percent error is -2.1352% of Jocelyn's estimate. May I have Brainless
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3 years ago
Read 2 more answers
Select the correct answer.
FromTheMoon [43]

The approximate area in square feet of the sides panel is 146.4 feet.

<h3>Area = 1 / 2 bh</h3>

where

b = base

h = height

Therefore, let's find the height and the base using trigonometric ratios.

sin 30 = opposite / hypotenuse

sin 30° = h / 26

cross multiply

h = 26 ×  1 / 2

h = 13 ft.

Let's find the base using Pythagoras theorem.

b² = 26² - 13²

b² = 676 - 169

b = √507

b = 22.5166604984

b = 22.52 ft

Area = 1 / 2 × 22.52 × 13

Area = 292.76 / 2

Area = 146.38 ≈ 146.4 ft


learn more on right angle triangle here: brainly.com/question/20999524?referrer=searchResults

8 0
2 years ago
7hr= how many minutes ​
denis-greek [22]

Answer:

420 minutes

Step-by-step explanation:

1 hour = 60 minutes

7 * 1 hour = 7 * 60 minutes

7 hours = 420 minutes

5 0
3 years ago
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Help me please this is due today
matrenka [14]

Answer:

LCM = 20, GCF = 9

Step-by-step explanation:

4 0
2 years ago
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During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
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