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White raven [17]
3 years ago
5

Let f(x)=−1/4(x+4)^2−8 . What is the average rate of change for the quadratic function from x=−2 to x = 2? Enter your answer in

the box.
Mathematics
1 answer:
kiruha [24]3 years ago
3 0

Answer:

Average rate of change of function is -2.

Step-by-step explanation:

Given f(x)=\frac{-1}{4}(x+4)^2-8.

we have to find the average rate of change for the quadratic function from x=−2 to x = 2.

f(-2)=\frac{-1}{4}(-2+4)^2-8=\frac{-1}{4}(4)-8=-9

f(2)=\frac{-1}{4}(2+4)^2-8=\frac{-1}{4}(36)-8=-17

The average rate of change of the function  f(x) on interval [-2,2] is

\frac{f(b)-f(a)}{b-a}=\frac{f(2)-f(-2)}{2-(-2)}=\frac{-17-(-9)}{4}=\frac{-8}{4}=-2

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****ASAP*****<br> can someone pls help me with this? and can you describe it please?
Studentka2010 [4]

Add 165 to 245. That is a total of 410kWh.

245kWh is more than 50% of 410kWh.

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4 years ago
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Zina [86]
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2 years ago
I need help with this
andre [41]

Answer:

  f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

__

Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

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Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

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Taken altogether, these factors give us the function ...

  \boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}

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