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White raven [17]
4 years ago
5

Let f(x)=−1/4(x+4)^2−8 . What is the average rate of change for the quadratic function from x=−2 to x = 2? Enter your answer in

the box.
Mathematics
1 answer:
kiruha [24]4 years ago
3 0

Answer:

Average rate of change of function is -2.

Step-by-step explanation:

Given f(x)=\frac{-1}{4}(x+4)^2-8.

we have to find the average rate of change for the quadratic function from x=−2 to x = 2.

f(-2)=\frac{-1}{4}(-2+4)^2-8=\frac{-1}{4}(4)-8=-9

f(2)=\frac{-1}{4}(2+4)^2-8=\frac{-1}{4}(36)-8=-17

The average rate of change of the function  f(x) on interval [-2,2] is

\frac{f(b)-f(a)}{b-a}=\frac{f(2)-f(-2)}{2-(-2)}=\frac{-17-(-9)}{4}=\frac{-8}{4}=-2

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I thought of a number, I added 1 3 4 to it, then I multiplied the result by 2 2 11 and I got 8. What was my number?
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Given:

In a number, adding 1\dfrac{3}{4}, then multiplying the result by 2\dfrac{2}{11} we get 8.

To find:

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Solution:

Let the unknown number be x.

According to the question,

(x+1\dfrac{3}{4})\times 2\dfrac{2}{11}=8

(x+\dfrac{1\times 4+3}{4})\times \dfrac{2\times 11+2}{11}=8

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Subtract \dfrac{7}{4} from both sides.

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x=\dfrac{44-21}{12}

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x=1\dfrac{11}{12}

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