The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11, k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
=( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1 )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is
Answer:
c < - 6
Step-by-step explanation:
Given
3(2c - 8) - 10c > 0 ← distribute and simplify left side
6c - 24 - 10c > 0
- 4c - 24 > 0 ( add 24 to both sides )
- 4c > 24
Divide both sides by - 4, reversing the inequality symbol as a consequence of dividing by a negative quantity.
c < - 6
We can solve for the length of side a to the nearest whole number using the Laws of Cosines such as the formula is shown below:
a²=b²+c²-2bcCosA
Solving for the value of a, we have:
a²=10²+14²-2(10)(14)cos54°
a²=131.42
a=11.46
The answer is 11.46 or 11.5.
Answer:
5 tripled is 15, x=5
Step-by-step explanation:
14-9=5 which is the number you're looking for, and 3×5=15
