The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Since 3in, 4in, and 8in. Since 6+14 > 10,6+ 10 > 14, and 10 + 14 > 6, you can form a triangle with the lengths 6m, 14m, and 10m.
Answer:
14. x=30, y=15, z=165
15. x=10, y=25
Step-by-step explanation:
Answer:
12x3+6x2+34x+17
Step-by-step explanation:
(2x+1)(6x2+8+9)
=(2x+1)(6x2+8+9)
=(2x)(6x2)+(2x)(8)+(2x)(9)+(1)(6x2)+(1)(8)+(1)(9)
=12x3+16x+18x+6x2+8+9
=12x3+6x2+34x+17
Answer:
46
Step-by-step explanation:
Click on the box for more details on how to <span>distributive property to express 30 + 75.</span>
