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Luden [163]
3 years ago
8

Tickets for a concert have been in incredibly high demand and as the date for the concert draws closer the price of tickets incr

eases exponentially The cost of a pair of concert tickets was $150 yesterday and today it is $162. as you complete parts a through C below assume that each days percent increase from the day before is the same.
Mathematics
1 answer:
Nitella [24]3 years ago
5 0
So we have two quantities and need to find out how much percentage it increased from one to another and then maybe write an equation that describes the behavior. Lets find the percentage raise between quantities using a simple rule of three, direct proportion:
<span>150 -----> 100</span>
162  ---->  x

x = (162)(100)/150
x = 108
that means that $162 is the 108% of $150, or that the tickets are raising their price by 8% daily. The problem states as well that the price grow is exponential, not expressed by a linear equation that is.
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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

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Likurg_2 [28]

In this question, it is given that the eighth term is 78 and the explicit formula is

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And the recursive formula is

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<em>Dividing both sides by 6, we get:</em>

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Therefore, the inequality for 'x' is given as:

x>-1

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