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LuckyWell [14K]
3 years ago
12

Technologies that function within the established system are called

Computers and Technology
1 answer:
vesna_86 [32]3 years ago
8 0
<span>Authorizing technologies are technologies that controls the use of system and network resources through authentication and authorization. 
</span><span>Enabling technologies are innovation technologies that drive radical change in the capabilities of a user or culture.
</span>Obstructing technologies include blocking<span> and filtering, content manipulation, attacks.
</span>Preemption means "prior seizure of" and preemptive technologies <span>take control of the operating system from one task and giving </span>it<span> to another task.
</span><span>Technologies that function within the established system are called enabling technologies.</span>
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Create an array of strings. Let the user decide how big this array is, but it must have at least 1 element. Prompt them until th
Brums [2.3K]

Answer:

lst = []

n = int(input("Input an array size for you words array: "))

print("Now please enter " + str(n) + " words")

max = 0

min = 1000

index_min = 0

index_max = 0

for i in range(n):

   s = input("Input a word: ")

   lst.append(s)

   if len(s) >= max:

       max = len(s)

       index_max = i

   if len(s) <= min:

       min = len(s)

       index_min = i

print("The longest word is :" + lst[index_max])

print("The shortest word is :" + lst[index_min])

Explanation:

Create an empty list, lst

Get the size from the user

Create a for loop that iterates "size" times

Inside the loop, get the strings from the user and put them in the lst. Find the longest and shortest strings and their indices using if structure.

When the loop is done, print the longest and shortest

5 0
4 years ago
Suppose end system A wants to send a large file to end system B. At a very high level, describe how end system A creates packets
sashaice [31]

Answer:

The answer is below

Explanation:

Suppose end system A wants to send a large file to end system B, the large file is first divided into smaller chunks. Each chunk is then assigned a header forming a packet. Multiple packets are being generated with each of the packet containing a unique destination address in its header.

When a packet arrives at the packet switch, the switch uses the unique destination address that is attached in the header of the packet to determine the link onto which the packet is to be forwarded.

5 0
3 years ago
The term __________ denotes data that is being stored on devices like a universal serial bus (USB) thumb drive, laptop, server,
kicyunya [14]

Answer:

B. data at rest, data in transit

Explanation:

A database management system (DBMS) can be defined as a collection of software applications that typically enables computer users to effectively and efficiently create, store, modify, retrieve, centralize and manage data or informations in a database. Thus, it allows computer users to efficiently retrieve and manage their data with an appropriate level of security.

Generally, a database management system (DBMS) acts as an intermediary between the physical data files stored on a computer system and any software application or program.

Data at rest refers to a form of data that is stored on devices such as; a universal serial bus (USB) thumb drive, laptop, server, DVD, CD, or server.

Data in transit is simply any data that exists in a mobile or dynamic state on the network, such as data on the Internet, wireless networks, or a private network.

8 0
3 years ago
After creating an organizational strategy based on porter's models, a company can?
malfutka [58]
1.B 2.B 3.C 4.B 5.B 6.C 7.A 8.A 9.C 10.A
3 0
3 years ago
Read 2 more answers
palindrome is a string that reads the same forwards as backwards. Using only a xed number of stacks, and a xed number of int and
bixtya [17]

Solution :

check_palindrome$(string)$

   lower_$case$_string$=$ string$. to$_lower()

   Let stack = new Stack()

   Let queue = new Queue();

   for each character c in lower_case_string:

       stack.push(c);

       queue.enqueue(c);

   let isPalindrome = true;

   while queue is not empty {

       if (queue.remove().equals(stack.pop())) {

           continue;

       } else {

           isPalindrome=false;

           break while loop;

       }

   }

   return isPalindrome

Input = aabb

output = true

input =abcd

output = false

6 0
3 years ago
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