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3 years ago

8

A city park, shaped a square , has an area of 2 square miles. The city manager wishes to calculate the perimeter of the park. Wh

ich is the correct perimeter and is the value rational or irrational?

2 answers:

Oksanka [162]3 years ago

7 0

Is this a multiple choice question?

AlladinOne [14]3 years ago

7 0

The perimeter is the square root of 2 multiplied by 4( no rational)

(sqr2 +sr2 +2 +sqr2 )

1

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What is the slope of the line that passes through (-4, 5) and (1, 3)?

Tasya [4]

M=-2/5 is the answer to this equation

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What is the slope of the line that passes through the points (-2,7) and (2,-5) in simplest form ?

creativ13 [48]

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3 years ago

4k^2 + 28k + 48 factor the polynomial

andreyandreev [35.5K]

4 (k+3) (k+) is the answer

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3 years ago

RideAnS [48]

Answer:

4.5 ft

Step-by-step explanation:

Given that the two fugures in the question above are similar, it means they have the same shape, even though they are if different sizes, the ratio of their corresponding sides are proportional. Thus,

18/x = 8/2

Let's solve for x as required.

We have,

18/x = 8/2

=>Cross multiply:

18 × 2 = 8 × x

36 = 8x

=>Divide both sides by 8

36/8 = x

4.5 = x

x = 4.5 ft

The first option is our answer = 4.5 ft

5 0

3 years ago

Write an equation of the perpendicular bisector of the line segment whose endpoints are (−1,1) and (7,−5)

icang [17]

The equation is $y = \frac{3}{2} x - \frac{11}{2}$

<u>Explanation:</u>

We have to first find the mid-point of the segment, the formula for which is

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$

So, the midpoint will be $(\frac{-1+7}{2} , \frac{1-5}{2} )\\\\$

= $(3,-2)$

It is the point at which the segment will be bisected.

Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula $\frac{y_2-y_1}{x_2-x_1}$

The slope is $\frac{-5-1}{7+1}$ = $-\frac{2}{3}$

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of $-\frac{2}{3}$ is $\frac{3}{2}$

To write an equation, substitute the values in y = mx + c

WHere,

y = -1

x = 3

m = 3/2

Solving for c:

$-1 = \frac{3}{2} X 3 + c\\\\-1 = \frac{9}{2}+c\\ \\c = \frac{-2-9}{2} \\\\c = \frac{-11}{2}$

Thus, the equation becomes:

$y = \frac{3}{2} x - \frac{11}{2}$

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3 years ago