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MA_775_DIABLO [31]
3 years ago
11

Write an equation of the perpendicular bisector of the line segment whose endpoints are (−1,1) and (7,−5)

Mathematics
1 answer:
icang [17]3 years ago
7 0

The equation is y = \frac{3}{2} x - \frac{11}{2}

<u>Explanation:</u>

We have to first find the mid-point of the segment, the formula for which is

(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )

So, the midpoint will be (\frac{-1+7}{2} , \frac{1-5}{2} )\\\\

                                  = (3,-2)

It is the point at which the segment will be bisected.

Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula \frac{y_2-y_1}{x_2-x_1}

The slope is \frac{-5-1}{7+1} = -\frac{2}{3}

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of  -\frac{2}{3} is \frac{3}{2}

To write an equation, substitute the values in y = mx + c

WHere,

y = -1

x = 3

m = 3/2

Solving for c:

-1 = \frac{3}{2} X 3 + c\\\\-1 = \frac{9}{2}+c\\ \\c = \frac{-2-9}{2} \\\\c = \frac{-11}{2}

Thus, the equation becomes:

y = \frac{3}{2} x - \frac{11}{2}

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