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3 years ago

11+8×{45+4×[3+8×(12×13-8×14)-37]}+1234=

1 answer:

7 0

11 + 8 × {45 + 4 × [3 + 8 × (12 × 13 - 8 × 14) - 37]} + 1234 =

= 11 + 8 × {45 + 4 × [3 + 8 × (156 - 112) - 37]} + 1234 =

= 11 + 8 × {45 + 4 × [3 + 8 × 44 - 37]} + 1234 =

= 11 + 8 × {45 + 4 × [3 + 352 - 37]} + 1234 =

= 11 + 8 × {45 + 4 × [355 - 37]} + 1234 =

= 11 + 8 × {45 + 4 × 318} + 1234 =

= 11 + 8 × {45 + 1272} + 1234 =

= 11 + 8 × 1317 + 1234 =

= 11 + 10536 + 1234 = 10547 + 1234 = 11781

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I cannot not give the correct solution, need more context. How many children are there, how many adults are in the family? So I will explain in my explanation.

Step-by-step explanation:

If more context were given, for example: 2 adults and 2 children.

Then the bakers would have bought 2 adult tickets for ___ each

Then the bakers would have bought 3 children's tickets for ___ each

So using what we know we can create an equation:

2A+3C=28,

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So we divide 28 by 5, which is the total amount of tickets.

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b) the bakers would have bought 3 children's tickets for 5.6 each.

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