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lawyer [7]
4 years ago
8

Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = ln(x2 + 5x + 12), [−3, 1]

Mathematics
1 answer:
Bezzdna [24]4 years ago
8 0
A graphing calculator shows the minimum to be located at the vertex of the quadratic, x = -2.5, and the maximum to be located at the right end of the interval.

The absolute maximum value of f(x) is ln(18) ≈ 2.89037.
The absolute minimum value of f(x) is ln(5.75) ≈ 1.74920.

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Step-by-step explanation:

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Answer:

The product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

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Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

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  • b is the y-intercept

Given the lines

y = 2/3 x -3       --- Line 1

y = -3/2x +2      --- Line 2

<u>The slope of line 1</u>

y = 2/3 x -3       --- Line 1

By comparing with the slope-intercept form of the line equation

The slope of line 1 is: m₁ = 2/3

<u>The slope of line 2</u>

y = -3/2x +2      --- Line 2

By comparing with the slope-intercept y = mx+b form of the line equation

The slope of line 2 is: m₂ = -3/2

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

m₁ × m₂ = (2/3)(-3/2 )

m₁ × m₂ = -1

Thus, the product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

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