it is just still 5 I believe :P hope this helps
Answer:
- sin = √(1 -cos²)
- tan = (√(1 -cos²))/cos
Step-by-step explanation:
![\displaystyle\sin^2{\theta}+\cos^2{\theta}=1 \qquad\text{Pythagorean identiy}\\\\\sin{\theta}=\sqrt{1-\cos^2{\theta}} \qquad\text{solved for sine}\\\\\tan{\theta}=\frac{\sin{\theta}}{\cos{\theta}}=\frac{\sqrt{1-\cos^2{\theta}}}{\cos{\theta}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csin%5E2%7B%5Ctheta%7D%2B%5Ccos%5E2%7B%5Ctheta%7D%3D1%20%5Cqquad%5Ctext%7BPythagorean%20identiy%7D%5C%5C%5C%5C%5Csin%7B%5Ctheta%7D%3D%5Csqrt%7B1-%5Ccos%5E2%7B%5Ctheta%7D%7D%20%5Cqquad%5Ctext%7Bsolved%20for%20sine%7D%5C%5C%5C%5C%5Ctan%7B%5Ctheta%7D%3D%5Cfrac%7B%5Csin%7B%5Ctheta%7D%7D%7B%5Ccos%7B%5Ctheta%7D%7D%3D%5Cfrac%7B%5Csqrt%7B1-%5Ccos%5E2%7B%5Ctheta%7D%7D%7D%7B%5Ccos%7B%5Ctheta%7D%7D)
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If you draw a triangle with a hypotenuse of 1 and an "adjacent" leg of "cos", then using the Pythagorean theorem, you can see that the "opposite" leg will be √(1-cos²) and the tangent will be (√(1-cos²))/cos. Whether or not you're allowed to draw such a triangle on paper, you can certainly do it in your mind.