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3 years ago

Find two solutions to each equation in the interval -90°<θ<270°

1 answer:

8 0

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Erika is working on solving the exponential equation 50x = 17; however, she is not quite sure where to start. using complete sen

Kryger [21]

Erika is working on solving the exponential equation 50^x = 17; The solution is x = 0.7242.

<h3>What is logarithm?</h3>

When you raise a number with an exponent, there comes a result.

Let's say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using a logarithm as follows

$b = \log_a(c)$

'a' is called base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'

Erika is working on solving the exponential equation 50^x = 17;

however, she is not quite sure where to start.

The equation is

$50^x = 17\\$

By taking the log both sides

$log_a b = x\\\\a_x = b$

By using the base formula

$log_0 y = \dfrac{logy}{log b}$

So, $log_{50} 17= x\\\\$

$x = \dfrac{log17}{log 50}$

x = 0.7242

Learn more about logarithm here:

brainly.com/question/20835449

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3 0

2 years ago

A certain town never has two sunny days in a row. Each day is classified as being either sunny, cloudy (but dry), or rainy. If i

11111nata11111 [884]

Answer:

the proportion of days that are Sunny is 0.2

Step-by-step explanation:

Given the data in the question;

Using markov chain;

3 states; Sunny(1), Cloudy(2) and Rainy(3)

Now, based on given conditions, the transition matrix can be obtained in the following way;

$\left[\begin{array}{ccc}0&0.5&0.5\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]$

so let the proportion of sunny, cloudy and rainy days be S, C and R respectively.

such that, from column 1

S = 0.25C + 0.25R -------------let this be equation 1

from column 2

0.5C = 0.5S + 0.25R

divided through by 0.5

C = S + 0.5R ---------------------- let this be equation 2

now putting equation 2 into equation;

S = 0.25(S + 0.5R) + 0.25R

S = 0.25S + 0.125R + 0.25R

S - 0.25S = 0.375R

0.75S = 0.375R

S = 0.375R / 0.75

S = 0.5R

Therefore,

from equation 2; C = S + 0.5R

input S = 0.5R

C = 0.5R + 0.5R

C = R

Now, we know that, the sum of the three proportion should be equal to one;

S + C + R = 1

since C = R and S = 0.5R

we substitute

0.5R + R + R = 1

2.5R = 1

R = 1/2.5

R = 0.4

Hence, the proportion of days that are Rainy is 0.4

C = R

C = 0.4

Hence, the proportion of days that are Cloudy is 0.4

S = 0.5R

S = 0.5(0.4)

S = 0.2

Hence, the proportion of days that are Sunny is 0.2

8 0

3 years ago

Complementary angles always sum to _____.

dmitriy555 [2]

The answer is: 90° .
______________________________________________________

5 0

3 years ago

Read 2 more answers

Y= -x +3 and y = x - 1

inysia [295]

Answer:

x=2 and y=1

Step-by-step explanation:

Rewrite equations:

y=−x+3;y=x−1

Step: Solve

y=−x+3

Step: Substitute−x+3foryiny=x−1:

y=x−1

−x+3=x−1

−x+3+−x=x−1+−x(Add -x to both sides)

−2x+3=−1

−2x+3+−3=−1+−3(Add -3 to both sides)

−2x=−4−2x−2=−4−2

(Divide both sides by -2)

x=2

Step: Substitute2forxiny=−x+3:

y=−x+3

y=−2+3

y=1(Simplify both sides of the equation)

Hope this Helps you :)

3 0

3 years ago

4 in. 7 in. O 124 6 in 87.9 in O 97.5 in O 78.9 in 5 6 7

Dima020 [189]

Answer:

v=3.14 r 2 h

3.14 (2)(2)(7)= 87.9

5 0

2 years ago