Solve these 3 separately, please!:

Mathematics

2 answers:

MAVERICK [17]3 years ago

6 0

Answer:

4-6w=16 is w=-2

-9-5r=-19 is r=2

5k-7=3k+3 is k=5

eimsori [14]3 years ago

6 0

Answers:
• w = -2
• r = 2
• k = 5

Explanation:
• Problem #1

Step 1 - Subtract four from both sides of the equation

4 - 6w = 16
4 - 4 - 6w = 16 - 4
-6w = 12

Step 2 - Divide both sides of the equation by negative six

-6w = 12
-6w/ -6 = 12/ -6
w = -2

• Problem #2

Step 1 - Add nine to both sides of the equation

-9 - 5r = -19
-9 + 9 - 5r = -19 + 9
-5r = -10

Step 2 - Divide both sides of the equation by negative five

-5r = -10
-5r/ -5 = -10/ -5
r = 2

• Problem #3

Step 1 - Add seven to both sides of the equation

5k - 7 = 3k + 3
5k - 7 + 7 = 3k + 3 + 7
5k = 3k + 10

Step 2 - Subtract 3k from both sides

5k = 3k + 10
5k - 3k = 3k - 3k + 10
2k = 10

Step 3 - Divide both sides of the equation by 2

2k = 10
2k/ 2 = 10/ 2
k = 5

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3 years ago

Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin

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Thus

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$\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 , y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}$

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