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Elina [12.6K]
3 years ago
6

PLEASE SOMEONE HELP ME WITH NUMBER 2. Only PLEASE I NEED HELP!!!!!

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
4 0

Answer:

The intersection of line l is AC

and the intersection of line m is DF.

dalvyx [7]3 years ago
3 0

Answer:

1. Line l can be named as line FBD

2. B and C

3. Colinear:-A,B,C

No-Colinear:-F,B,C

4. 6

5. DE = 13

2 + 2x - 3 = 13

2x - 1 = 13

2x = 12

x = 12/2

x = 6

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12 1/2 percent multiple 64<br>​
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A farmer has enough feed to last his 15pigs for 20days. How long would the feed last if he had 10pigs​
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40/3 days, (13.33 days)

Step-by-step explanation:

Set up the equation, 15/20 = 10/x, and then use cross mutiply to solve it.

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3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

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