At the end of dinner, equivalant amounts of lasagna in two pans were left.
1 answer:
You might be interested in
Answer:
0.281 = 28.1% probability a given player averaged less than 190.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A bowling leagues mean score is 197 with a standard deviation of 12.
This means that
What is the probability a given player averaged less than 190?
This is the p-value of Z when X = 190.
has a p-value of 0.281.
0.281 = 28.1% probability a given player averaged less than 190.
Answer:
- length 3 in
- width 2 in
Step-by-step explanation:
Since none of the answer choices match the drawing of the gardener, we assume the question is referring to the drawing of the partner.
The gardener's drawing is 1/4 of actual size. So, in terms of the gardener's drawing, actual size is ...
gardener's drawing = (1/4)actual size
actual size = 4(gardener's drawing)
__
The partner's drawing is 1/20 of actual size, so is ...
partner's drawing = actual size/20 = (4(gardener's drawing))/20
partner's drawing = (4/20)(gardener's drawing)
partner's drawing = (gardener's drawing)/5
__
Then the {length, width} of the partner's drawing are ...
partner's drawing {length, width} = {15 in, 10 in}/5 = {3 in, 2 in}
The partner's drawing has a length of 3 inches and a width of 2 inches.
