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3 years ago

What is the result of subtracting a number greater than -3 and less than -2 from a number greater than 1 and less than 6

Mathematics

1 answer:

SVEN [57.7K]3 years ago

8 0

Answer:

3 < M - N < 9

Step-by-step explanation:

First, let's write the inequalities for these two numbers.

"a number greater than -3 and less than -2"

-3 < N < -2

"a number greater than 1 and less than 6"

1 < M < 6

We want to subtract the first one to the second one, so we want to get:

M - N

Because this is a subtraction, the lower bound of the subtraction happens when we have the minimum value of M and the maximum value of N.

Then the minimum value of M - N happens when:

M = 1

N = -2

(notice that M can't be equal to 1, and N can't be equal to -2, we just do this to find the lower bound)

Then the lower bound is:

M - N = 1 - (-2) = 3

We already got:

3 < M - N

For the upper bound, we need to find the difference between the largest value of M, and the lowest value of N

This is:

M = 6

N = -3

M - N = 6 - (-3) = 9

Then:

M - N < 9

If we take both of our results, the possible values of the subtraction are given by:

3 < M - N < 9

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Write a rule for the nth term of the arithmetic sequence:<br><br> a11= 50, d = 7

ivolga24 [154]

Answer:

Required rule for $n^{th}$ is $a_{n}=7n-27$ .

Step-by-step explanation:

Given that,

$a_{11} = 50,\ \ d=7$

From the question: we have to write the $n^{th}$ term of Arithmetic sequence.

Arithmetic Sequence or Arithmetic progression (A.P) : It is a sequence which possess that difference between of two successive sequence is always constant.

$a_{1} ,a_{2},a_{3},a_{4}.....................a_{n-1},a_{n}$

where, $a_{1}$ is the first term of A.P

$d$ is the common difference.

$a_{n}$ is the last term or general term.

The above sequence to be in A.P then their common difference should be equal.

$d=a_{2}-a_{1} =a_{3}-a_{2}=a_{4} -a_{3} ..........................a_{n}-a_{n-1}$

Now, Formula of General Term is $a_{n}=a+(n-1)d$

So, $a_{11}= a+(11-1)d\\ a_{11} = a+10d$

Substituting the value of $a_{11} = 50,\ \ d=7$ we get,

$50=a+10\times7\\50=a+70\\a=-20$

Then General term ( $a_{n}$ ) of given data is

$a_{n}=-20+(n-1)7\\a_{n}=-20+7n-7\\a_{n}=7n-27$

Therefore, Required rule for $n^{th}$ is $a_{n}=7n-27$ .

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Math question quadratics

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Answer: The length and width are 50 and 30 meters (or 30 and 50 meters).

Step-by-step explanation:

To solve this question, we can represent variables for the length and width in two equations.

$2l + 2w = 160\\\\l * w= 1500$

To solve for one of the variables, you'll have to substitute one of the variables, so solve for one of them:

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Now, we have a standard quadratic equation that we can factor. When factoring, you'll get this:

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This tells us that the width could be either 50 or 30.

Substitute 50 into one of the equations to find the length:

2 (l) + 100 = 160

l = 30.

The length and width are 50 and 30 meters (or 30 and 50 meters).

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