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3 years ago

13

What is the slope of the line that passes through the points (1,3) and (5,-2)

1 answer:

bija089 [108]3 years ago

7 0

A

Hope this helped :)

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Carla's team won 3 of its 5 games. Elena's team won games at the same rate and won 12 games. How many games did Elena's team pla

Maurinko [17]

This is all about proportions. You can make this into fractions:

3/5 = 12/x

A good way to handle this, is to make one of those numbers the same. If you do (3/5) * 4, you would get 12/20 (because 4 * 3 = 12 and 4 * 5 = 20)

So then you have this:

12/20 = 12/x

It's basically a fill in the blank from there. x= 20

Elena's team played 20 games

4 0

3 years ago

Read 2 more answers

Of the 32 students in a certain class, 15 are in a music club and 20 are in a dance club. if 10 of the students are not in eithe

mel-nik [20]

There are a total of 35 in the two clubs and 10 not in either. That makes 45 students, however there are only 32 in the class which means 45-32 = 13 students in BOTH clubs. So if we want to find how many are in only one club we can say 32 = 13 + 10 + x

x = 9 students in only one club

8 0

3 years ago

The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.

melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

The common ratio is: $\mathbf{r = \frac{a + 5d}{a + d}}$
The general term of the GP is: $\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

The nth term of an AP is:

$\mathbf{T_n = a + (n - 1)d}$

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

$\mathbf{T_2 = a + d}$

$\mathbf{T_6 = a + 5d}$

$\mathbf{T_8 = a + 7d}$

The <em>first, second and third terms </em>of the GP would be:

$\mathbf{a_1 = a + d}$

$\mathbf{a_2 = a + 5d}$

$\mathbf{a_3 = a + 7d}$

The common ratio (r) is calculated as:

$\mathbf{r = \frac{a_2}{a_1}}$

This gives

$\mathbf{r = \frac{a + 5d}{a + d}}$

The nth term of a GP is calculated using:

$\mathbf{a_n = a_1r^{n-1}}$

So, we have:

$\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0

3 years ago

The diagram shows the sector of a circle with the centre O and radius 6cm.

cricket20 [7]

Answer:

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN = $\frac{\theta}{360}(\pi r^{2})$

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN = $\frac{50}{360}(\pi )(6)^2$

= 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN = $\frac{1}{2}(OP)(PN)$

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) = $\frac{PN}{ON}$

PN = ONsin(25°)

= 6sin(25°)

= 2.536 cm²

cos(25°) = $\frac{OP}{ON}$

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

= 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

≈ 1.92 cm²

3 0

3 years ago

the roof of the school has a rise of 3.6 meters and a run of 12 meters. what is the slope/pitch of the roof?

goldenfox [79]

Answer:

The slope will be:

slope = 0.3

Step-by-step explanation:

As we know that the slope of a certain line is basically the measure of its steepness.

Mathematically, the slope can be calculated as 'rise over run'.

In other words, the 'rise' is 'change in y', and 'run' is 'change in x'.

Given

The roof of the school has a rise = 3.6 meters = rise = change in y

The roof of the school has a run = 12 meters = run = change in x

So the slope will be:

slope = rise ÷ run

= 3.6 ÷ 12

= 0.3 ∵( 3.6 ÷ 12 = 0.3)

Therefore, the slope will be:

slope = 0.3

5 0

2 years ago