What is the slope of the line that passes through the points (1,3) and (5,-2)
1 answer:
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Answer:
Intercepts:
x = 0, y = 0
x = 1.77, y = 0
x = 2.51, y = 0
Critical points:
x = 1.25, y = 4
x = 2.17 , y = -4
x = 2.8, y = 4
Inflection points:
x = 0.81, y = 2.44
x = 1.81, y = -0.54
x = 2.52, y = 0.27
Step-by-step explanation:
We can find the intercept by setting f(x) = 0
where n = 0, 1, 2,3, 4, 5,...
Since we are restricting x between 0 and 3 we can stop at n = 2
So the function f(x) intercepts at y = 0 and x:
x = 0
x = 1.77
x = 2.51
The critical points occur at the first derivative = 0
or
where n = 0, 1, 2, 3
Since we are restricting x between 0 and 3 we can stop at n = 2
So our critical points are at
x = 1.25,
x = 2.17
,
x = 2.8,
For the inflection point, we can take the 2nd derivative and set it to 0
We can solve this numerically to get the inflection points are at
x = 0.81,
x = 1.81,
x = 2.52,
Answer:
Step-by-step explanation:
Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form
Because the parameter is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.
Replacing the parameter value, we have
Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is .