3 years ago

Anonymous 3 years ago

Mathematics

1 answer:

scZoUnD [109]3 years ago

8 0

I'm in 7th grade and I need help with my math homework

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Please help me I’m stuck

FrozenT [24]

Answer:

10.77 units

Step-by-step explanation:

By imaging an imaginery line at point before 1 units to be 4 units: b = 4 units

Therefore h = 11 - 1 = 10 units

Using Pythagoras theorem:

x² = h² + b² = 10² + 4² = 100 + 16 = 116

x = √116 = 10.77 units

8 0

3 years ago

Akikta bought 25 trees for $15.40 each. Chloe bought 35 trees for $14.30 each. What was the difference between the total amounts

cupoosta [38]

Answer: $115.50

Step-by-step explanation:

500.5-385 = x

3 0

3 years ago

What is the slope of this line? A: - 1/3 B: - 2/3 C: 2/3 D: 1/3

bezimeni [28]

Answer:

The answer is C. 2/3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can someone solve this for me?

Sav [38]

Answer:

Step-by-step explanation:

9 is 3/4*12.

3 0

3 years ago

If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly

cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^n-x$ , where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

$P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%$

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0

3 years ago