All categories

3 years ago

Find the inverse of the given relation. {(9, –14), (–7, 4), (6, –8)}

Mathematics

1 answer:

Law Incorporation [45]3 years ago

7 0

Answer:

{(-14,9),(4,-7),(-8,6)}.

Step-by-step explanation:

To find the inverse you just swap x and y.

So if (a,b) is a point on the relation then (b,a) is on it's inverse.

So the inverse of {(9, –14), (–7, 4), (6, –8)} is:

{(-14,9),(4,-7),(-8,6)}.

You might be interested in

Pls help me it would be nice !!!

notsponge [240]

Answer:

y=−3x−10

That is the equation in slope intercept form.

5 0

3 years ago

Need help with this math

UNO [17]

Step-by-step explanation:

set up a proportion for a.

225/30=x/195. x=1462.5 milligrams daily

for b, if he gets 700 mg every 8 hours he only gets it 3 times a day. 700*3 is 2100, which means he is overdosing

7 0

3 years ago

There were 18 grey wolves after three years there were 27 grey wolves what is the percent increase

goldfiish [28.3K]

27-18= 9
9/18 x100= 50
There was a 50% increase in grey wolves

3 0

3 years ago

100p for an answer please help!!!!!!!!!!!

djyliett [7]

The second option down, "nine times the difference of a number cubed and three", is the correct answer.

8 0

3 years ago

Read 2 more answers

Use the method of cylindrical shells to write out an integral formula for the volume of the solid generated by rotating the regi

vredina [299]

Answer:

The answer is " $\frac{5\pi}{6}$ "

Step-by-step explanation:

Please find the graph file.

$h= y=2x-x^2\\\\r= x\\\\Area=2\pi\times r\times h\\\\= 2 \pi \times x \times (2x-x^2)\\\\= 2 \pi \times 2x^2-x^3\\\\volume \ V(x)=\int \ A(x)\ dx\\\\= \int^{x=1}_{x=0} 2\pi (2x^2-x^3)\ dx\\\\= 2\pi [(\frac{2x^3}{3}-\frac{x^4}{4})]^{1}_{0} \\\\= 2\pi [(\frac{2}{3}-\frac{1}{4})-(0-0)] \\\\= 2\pi \times \frac{5}{12}\\\\=\frac{5\pi}{6}\\\\$

3 0

2 years ago