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emmainna [20.7K]
2 years ago
7

Teresa planted marigolds into 2/8 of her garden and petunias in 3/8 of her garden what fraction of the garden has marigolds and

petunias.​
Mathematics
1 answer:
igomit [66]2 years ago
8 0

Answer:

5/8

Step-by-step explanation:

Let x represent the size of her garden

m represent Marigolds

p represents petunias

She planted M into 2/8 of x

and also planted p into 3/8 of x

Fraction of the garden that has M and p will be:

(2/8 of x) +  (3/8 of x)

5/8 x

Hence, 5/8 of her garden has marigolds and petunias

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Angelo is making a rectangular floor for a clubhouse with an area of 84 square feet. The length if each side of the floor is a w
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Answer:

L=1 ft and B=84 ft

L=2 ft and B=42 ft

L=4ft and B=21ft

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L=7ft and B=12ft

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Step-by-step explanation:

We are given that

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We have to find the possible length and width of for Angelo's clubhouse.

Area of rectangle=length\times breadth

Using the formula

Area of rectangular floor for clubhouse=84 square feet

Length(L)\times breadth(B)=84

Factor of 84 are

1,2,4,6,7,12,14,21,42,84

Therefore,  possible dimension of rectangular floor

1ft\times 84ft,2ft\times 42ft,4ft\times 21ft,6ft\times 14ft,7ft\times 12ft,12ft\times 7ft,14ft\times 6ft,21ft\times 4ft,42ft\times 2ft,84ft\times 1ft

L=1 ft and B=84 ft

L=2 ft and B=42 ft

L=4ft and B=21ft

L=6ft and B=14 ft

L=7ft and B=12ft

L=12 ft and B=7ft

L=14ft and B=6 ft

L=21 ft and B=4 ft

L=42 ft and B=2 ft

L=84 ft and B=1 ft

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