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Ulleksa [173]
3 years ago
6

The length of a rectangle is 99 cm less than four timesfour times its width. if the area of the rectangle is 1313 cm2​, find the

dimensions of the rectangle.
Mathematics
1 answer:
serg [7]3 years ago
6 0
<span>
try using the formula length times width. It helps me so it should help you.



The length of a rectangle is 99 cm less than four timesfour times its width. if the area of the rectangle is 1313 cm2 , find the dimensions of the rectangle.</span>
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Dane są długości przyprostokątnych trójkąta prostokątnego .Oblicz długość jego przeciwprostokątnej .Do obliczeń możesz użyć kalk
Lina20 [59]

Answer:

26

75

37

82

145

34

Step-by-step explanation:

Hypotenuse of a right angle triangle from pythagoras theorem is given by

h²=b²+a²

Making h the subject

h=√(b²+a²)

Where h is hypotenuse, b is base and a is the other side of a triangle

10²+24²=676

√676=26 units

72²+21²=5625

√5625=75 units

12²+35²=1369

√1369=37 units

18²+80²=6724

√6724=82 units

105²+100²=21025

√21025=145 units

16²+30²=1156

√1156=34 units

5 0
3 years ago
What if the diameter of the inner sphere is 1.8 meters. What is the volume of the inflated space?
Alona [7]

Answer:

Volume is 3.05m³

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, sphere

Step one

The formula for the volume of a sphere is expressed as

V=4/3πr³

Step two

Given data

Diameter d = 1.8m

Radius r = d/2= 1.8/2= 0.9m

Step three

Substituting our given data we have

V= 4/3*3.142*0.9³

V= 4/3*3.142*0.729

V= 9.162/3

V=3.05m³

4 0
3 years ago
Rhonda has $4.85 in coins. If she has six more nickels than dimes and twice as many quarters as dimes, how many coins of each ty
Novay_Z [31]

Answer: nickels = 13, dimes = 7, quarters = 14

<u>Step-by-step explanation:</u>

First, set up the equations for each coin:

\begin {array}{c|c|c|l}\underline{\quad Type\quad }&\underline{Value}&\underline{Quantity}&\underline{\qquad \qquad \qquad Equation\qquad }\\ Nickel& \$0.05&6+d&0.05(6+d) = 0.30 + 0.05d\\Dime& \$0.10&d&\qquad 0.10(d)=0.10d\\Quarter& \$0.25&2d&\qquad 0.25(2d)=0.50d\\\end{array}

Next, the sum of the coins is $4.85 so substitute and solve for the variable:

   Nickels         +   Dimes  +   Quarters = Sum

(0.30 + 0.05d)  +    0.10d   +     0.50d   =  4.85

0.30 + 0.65d = 4.85

            0.65d = 4.55

                    d = 7

Lastly, plug the d-value into the quantity equation for the nickels and quarters to find their quantity.

nickels: 6 + d   = 6 + (7)   = 13

quarters: 2d   = 2(7)   = 14

6 0
3 years ago
12&lt;2x+2≤22 plz help me tnx
Alja [10]

Firstly, subtract 2 from all sides of this inequality: 10

Next, divide by 2 on all sides of the inequality and <u>your answer will be 5</u>

7 0
3 years ago
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
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