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Otrada [13]
3 years ago
5

If Number = 7, what will be displayed after code corresponding to the following pseudocode is run? (In the answer options, new l

ines are separated by semi-colons.) For (Count = 5; Count <= Number; Count++) Write Count + ", " + Count * 2 End For
Computers and Technology
1 answer:
kherson [118]3 years ago
8 0

Answer:

5,10; 6,12; 7,14

Explanation:

We will demonstrate the iteration of the loop:

First iteration: Number = 7, Count = 5 at the beginning. We will check if Count <= Number? Since it is correct, prints 5,10. Increment the Count by 1.

Second iteration: Number = 7, Count = 6. We will check if Count <= Number? Since it is correct, prints 6,12. Increment the Count by 1.

Third iteration: Number = 7, Count = 7. We will check if Count <= Number? Since it is correct, prints 7,14. Increment the Count by 1.

Forth iteration: Number = 7, Count = 8. We will check if Count <= Number? Since it is not correct, the loop stops.

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#include<iostream>

using namespace std;

//main function

int main(){

   //initialize the variables

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   //print the message

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Explanation:

Create the main function and declare the variable side.

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