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andreev551 [17]
3 years ago
12

SOMEONE PLEASE HELP MEEE!!!! HOW DO YOU DO THIS

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

A. 162 m²

Step-by-step explanation:

==>Given:

Isosceles trapezoid with:

base a = 19m

base b = 35m

Perimeter = 74meters

==>Required:

Area of trapezoid

==>Solution:

Recall: the length of the legs of an isosceles trapezoid are equal.

Perimeter of isosceles trapezoid = sum of the parallel sides + 2(length of a leg of the trapezoid)

Let l = leg of trapezoid.

Perimeter = 74m

Sum of parallel sides = a+b = 19+35 = 54m

Thus,

74 = 54 + 2(l)

74 - 54 = 2(l)

20 = 2(l)

l = 20/2 = 10m

Let's find area:

Area = ½(a+b)*h

a = 19

b = 35

h = ?

Using Pythagorean theorem, let's find h as follows:

h² = l² - [(35-19)/2)²

h² = 10² - [16/2]²

h² = 100 - 64

h² = 36

h = √36 = 6m

Area = ½ x (a+b) × h

= ½ × (19+35) × 6

= ½ × 54 × 6

= 27 × 6

Area = 162m²

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lbvjy [14]

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3 years ago
HELP! Will give branliest!!
nirvana33 [79]

Answer:

10y + 29 ≤ -23

Step-by-step explanation:

subtract 29 from each side to get:

10y ≤ -52

y ≤ -5.2

3 0
3 years ago
Here 1 more than BIG PRIZE
Firlakuza [10]
Hey there! :D

Use the distributive property.

a(b+c)= ab+ac

6(9x+2)+2x

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56x+ 12 <== equivalent expression

I hope this helps!
~kaikers
4 0
3 years ago
Can you help me with my work
andrezito [222]

Answer:

1. x = ±9

2. x=\pm \sqrt{13}

3. 12 and -12.

4. Antoine is incorrect. There exists two solutions x=5 and x= -5.

Step-by-step explanation:

According to the questions,

Problem 1. x^{2}-81=0 i.e. x^{2}=81 i.e. x = ±9.

Problem 2. 2x^{2}-26=0 i.e. x^{2}-13=0 i.e. x^{2}=13 i.e. x=\pm \sqrt{13}

Problem 3. [tex]f(x)=x^{2}-144[tex]

To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.

Thus, the options are 12 and -12.

Problem 4. We have [tex]f(x)=x^{2}+25[tex]

For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.

Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.

8 0
3 years ago
Ann Torbert purchased a truck for $11,000 on January 1, 2014. The truck will have an estimated salvage value of $1,000 at the en
alexandr402 [8]

Answer:

Balance in accumulated depreciation=\frac{10000}{Total Estimated Value}*Units of activity

Step-by-step explanation:

Salvage value=$1000

Purchased value=$11,000

In order to find the balance in accumulated depreciation at december 31,2015 using the units of activity we will use the following formula:

Balance in accumulated depreciation=\frac{10000}{Total Estimated Value}*Units of activity

In the above equation $10000 came from Purchased value - salvage Value

6 0
3 years ago
Read 2 more answers
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