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Mashutka [201]
3 years ago
10

Here is a square pizza with an area of 36 square inches. What length of stuffed crust will be around the edge?

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0
6 inches. Because the square root of 36 is 6 :)
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A rectangular field is 27 meters long and 18 meters wide. If fencing costs $12 per yard how much will it cost to enclose the fie
KiRa [710]

Find the perimeter of the field:

The dimensions are given in meters.

Perimeter = 27 +27 +18 +18 = 90 meters.

The price is given in price per yards, so now convert meters to yards:

1 meter = 1.09361 yards

90 meters x 1.09361 = 98.4252 yards.

Now multiply total yards by price per yard:

98.4252 x 12 = $1,181.10

4 0
3 years ago
Find the opposite of the integer -5.
VLD [36.1K]

Answer:

5

Step-by-step explanation:

The opposite of -5 is 5. You find this opposite by switching the negative sign to a positive sign.

3 0
3 years ago
Read 2 more answers
A Relation Is Shown In The Graph Below. Write Out The Ordered Pairs For The Inverse, And Determine If The Inverse Is A Function
Alexus [3.1K]
The 2nd selection is correct.

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If your relation has some point (x1, y1), the inverse relation has the point (y1, x1). For example, one of the points of your relation is (-1, 0), so (0, -1) will be a point in the inverse relation.

A relation is a function if it does not contain two or more points with the same x-value.

(The relation shown in the graph is NOT a function, but its inverse relation IS a function.)
7 0
3 years ago
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The drawing shows a stack of alternating cups. The cups are 9.2 cm high. How many cups will fit in a door that is 211.77 cm high
KIM [24]

Answer:

The total number of whole cups that we can fit in the dispenser is 25

Step-by-step explanation:

It is given that the height of each cup is 20 cm.

But when we stack them one on top of the other, they only add a height of 0.8 to the stack.  

The stack of cups has to be put in a dispenser of height 30 cm.

So we need o find out how many cups can fit in the dispenser.

Since the first cup is 20 cm high, the height cannot be reduced. So the space to fit in the remaining cups in the stack is only 30-20 cm as that’s the remaining space in the dispenser

So,

30 - 20 = 10 cm

To stack the other cups we have 10 cm of height remaining

As we know that addition of each adds 0.8 cm to the stack, the total number of cups that can be fit in the dispenser can be calculated by the following equation. Let the number of cups other than the first cup be denoted by ‘x’.

10 + 0.8x = 30

0.8x = 20

x = 25

The total number of cups that we can fit in dispenser is 25

7 0
3 years ago
A 39-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate
LenaWriter [7]

Answer:

The area of the triangle formed is increasing at a rate of 29.75 square feet per second.

Step-by-step explanation:

A 39-foot ladder is leaning against a vertical wall. We are given that the bottom of the ladder is being pulled away at a rate of two feet per second, and we want to find the rate at which the area of the triangle being formed is is changing when the bottom of the ladder is 15 feet from the wall.

Please refer to the diagram below. <em>x</em> is the distance from the bottom of the ladder to the wall and <em>y</em> is the height of the ladder on the wall.

According to the Pythagorean Theorem:

\displaystyle x^2+y^2=1521

Let's take the derivative of both sides with respect to time <em>t</em>. Hence:

\displaystyle \frac{d}{dt}\left[x^2+y^2\right] = \frac{d}{dt}\left[ 1521\right]

Implicitly differentiate:

\displaystyle 2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0

Simplify:

\displaystyle x\frac{dx}{dt} + y \frac{dy}{dt} = 0

The area of the triangle formed will be given by:

\displaystyle A  = \frac{1}{2} xy

Again, let's take the derivative of both sides with respect to time <em>t: </em>

<em />\displaystyle \frac{dA}{dt} = \frac{d}{dt}\left[\frac{1}{2}xy\right]<em />

From the Product Rule:

\displaystyle \frac{dA}{dt} = \frac{1}{2}\left(y\frac{dx}{dt} + x\frac{dy}{dt}\right)

At that instant, the ladder is 15 feet from the base of the wall. So, <em>x</em> = 15. Using this information, find <em>y</em>.

\displaystyle y = \sqrt{1521-(15)^2}=36

The bottom of the ladder is being pulled away from the wall at a rate of two feet per second. So, dx/dt = 2. Using this information and the first equation, find dy/dt:

\displaystyle \frac{dy}{dt} =-\frac{x\dfrac{dx}{dt}}{y}

Evaluate for dy/dt:

\displaystyle \frac{dy}{dt} = -\frac{(15)(2)}{(36)}=-\frac{5}{6}

Finally, using dA/dt, substitute in appropriate values:

\displaystyle \frac{dA}{dt} = \frac{1}{2}\left((36)(2)+(15)\left(-\frac{5}{6}\right)\right)

Evaluate. Hence:

\displaystyle \frac{dA}{dt} = \frac{119\text{ ft}^2}{4\text{ s}} = 29.75\text{ ft$^2$/s}

The area of the triangle formed is increasing at a rate of 29.75 square feet per second.

8 0
3 years ago
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